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immpy
Joined: 06 May 2017
Posts: 574
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 Posted: Fri Jan 21, 2022 6:08 pm Post subject: VH+ 012122 |
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Hello all, enjoy the puzzle.
| Code: |
+-------+-------+-------+
| . . 5 | . 1 . | . 6 . |
| . 9 . | 3 . 6 | 7 . . |
| 3 . . | 4 7 . | 9 . . |
+-------+-------+-------+
| 8 . . | . 9 . | . 4 . |
| 9 . . | 6 . 5 | . . 7 |
| . 4 . | . 8 . | . . 9 |
+-------+-------+-------+
| . . 8 | . 2 9 | . . 6 |
| . . 2 | 5 . 4 | . 9 . |
| . 6 . | . . . | 5 . . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
cheers...immp |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Jan 21, 2022 9:13 pm Post subject: |
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Doesn't really matter what you put in r5c7. Either way r4c9 < > 1. (a-d)
| Code: | +--------------+--------------+--------------+
| 27 78 5 | 9 1 28 | 3 6 4 |
| 12 9 4 | 3 5 6 | 7 128 128 |
| 3 18 6 | 4 7 28 | 9 12 5 |
+--------------+--------------+--------------+
| 8 5 137 | 2 9 137 | 6 4 13d |
| 9 2 13 | 6 4 5 | 18a 138 7 |
| 6 4 137 | 17 8 137 | 2 5 9 |
+--------------+--------------+--------------+
| 5 13 8 | 17 2 9 | 4 137 6 |
| 17 137 2 | 5 6 4 | 18b 9 138c |
| 4 6 9 | 8 3 17 | 5 127 12 |
+--------------+--------------+--------------+ |
Thanks Immp!
Last edited by Mogulmeister on Tue Jan 25, 2022 4:49 pm; edited 1 time in total |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Mon Jan 24, 2022 11:46 am Post subject: |
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| On a solving note, this came to me when I saw what I thought was going to be a skyscraper on 1's ab and cd. The extra 1's in r29c9 put paid to that idea but then I noticed that the cd "leg" had another strong link on 3's which turned it into something a bit different. |
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TomC
Joined: 30 Oct 2020
Posts: 359
Location: Wales
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| Posted: Tue Jan 25, 2022 3:03 pm Post subject: |
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This took me a little while to understand this solution
I now can see it as if c=3, d=1, a=8 and then no <8> in box 9 |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Jan 25, 2022 4:12 pm Post subject: |
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In general if you see 3 strong links in a four sided structure it’s worth looking at. Whether a is 1 or 8 it eliminates 1 from r4c9.
Equally you could set r4c9 to 1 and your contradiction loop d-a-b-c would throw out the 1 you started with in r4c9 |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Jan 25, 2022 4:46 pm Post subject: |
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The ANP <137> in r8c12 also comes to the same conclusion:
ANP true and r8c7 = 8 r5c7 =1 and r4c9 < > 1
ANP false and r7c2 =1 r7c4= 7 r7c8 =3 so r5c8 < > 3 and r4c9 = 3 (< >1) |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Jan 25, 2022 5:01 pm Post subject: |
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| TomC wrote: | This took me a little while to understand this solution
I now can see it as if c=3, d=1, a=8 and then no <8> in box 9 |
Or.....c=3 d=1 so a=8
and at the same time
c=3 and b=8
Two 8's in column 7 |
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