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immpy
Joined: 06 May 2017
Posts: 574
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 Posted: Mon Oct 25, 2021 6:06 pm Post subject: VH+ 102521 |
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Hello all, enjoy the puzzle...
| Code: |
+-------+-------+-------+
| 4 9 1 | . 2 . | . . . |
| . . . | 7 . . | . . 1 |
| . . . | . 5 . | 4 . . |
+-------+-------+-------+
| 5 . . | . 7 3 | 8 . 2 |
| 2 . . | . . . | . . 3 |
| 3 1 4 | 6 8 . | . . 7 |
+-------+-------+-------+
| . . 5 | . 4 . | . . . |
| 7 . . | . . 5 | . . . |
| . . . | . 3 . | 2 5 4 |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
cheers...immp |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Oct 26, 2021 9:51 am Post subject: |
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After basics.
| Code: | +--------------+----------------+----------------+
| 4 9 1 | 38 2 68 | 37 3678 5 |
| 68 5 23 | 7 69 4 | 39 2368 1 |
| 68 23 7 | 1389 5 1689 | 4 2368 689 |
+--------------+----------------+----------------+
| 5 6 9 | 4 7 3 | 8 1 2 |
| 2 7 8 | 5 19 19 | 6 4 3 |
| 3 1 4 | 6 8 2 | 5 9 7 |
+--------------+----------------+----------------+
| 19 23 5 | 1289 4 1689 | 1379 3678 689 |
| 7 4 23 | 1289 169 5 | 139 368 689 |
| 19 8 6 | 19 3 7 | 2 5 4 |
+--------------+----------------+----------------+ |
Thanks Immp!
I was tinkering with this and made a discovery.
If r2c7 = 3 then r2c3 =2 and puzzle solved. (four <23> chained together like a "spine")
-OR-
If r2c7 = 9 then stte and puzzle solved.(r2c3 = 2)
Whichever you choose for r2c7 we have a winner!
Last edited by Mogulmeister on Wed Oct 27, 2021 8:58 am; edited 1 time in total |
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Clement
Joined: 24 Apr 2006
Posts: 1113
Location: Dar es Salaam Tanzania
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| Posted: Tue Oct 26, 2021 1:37 pm Post subject: VH + 102521 |
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| Code: |
+------------------+-----------------------+-----------------------+
| 4 9 1 | 38 2 68 | 37 3678 5 |
| 68 5 c23 | 7 69 4 |c39 2368 1 |
| 68 23 7 | 1389 5 1689 | 4 2368 68-9|
+------------------+-----------------------+-----------------------+
| 5 6 9 | 4 7 3 | 8 1 2 |
| 2 7 8 | 5 19 19 | 6 4 3 |
| 3 1 4 | 6 8 2 | 5 9 7 |
+------------------+-----------------------+-----------------------+
| 19 23 5 | 1289 4 1689 | 1379 3678 a689 |
| 7 4 b23 | 1289 169 5 | 139 a368 a689 |
| 19 8 6 | 19 3 7 | 2 5 4 |
+------------------+-----------------------+-----------------------+
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(9=6|83)b9p365 – (3=2)r8c3 – (2=39)r2c37 => - 9r3c9; stte |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Oct 26, 2021 2:22 pm Post subject: |
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Another contradiction.
Using Clement's annotated grid we can also start in a different place (c)r2c7.
c(3-9)r2c7=(9-68)r3c9=a(68-9)r78c9=a(3-68)r8c8-b(3=2)r8c3-(2=3)r2c3-c(3=9)r2c7
Remove 9 in r2c7 and the loop contradicts it and puts the 9 back into r2c7.
R2c7 = 9. |
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TomC
Joined: 30 Oct 2020
Posts: 359
Location: Wales
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| Posted: Tue Oct 26, 2021 5:44 pm Post subject: |
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I used pincers on 3 in r1c4 and r2c7 to give -3 in r1c78
this sets r1c7 and r7c8 to 7
and this means -3 in r8c8 using the <23> in c3 otherwise no 3's in box 3
so r2c7=9
Bit of a scenic route here! |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Wed Oct 27, 2021 9:02 am Post subject: |
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| Nice wing at the start there Tom to set the contradiction rolling. |
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dongrave
Joined: 06 Mar 2014
Posts: 572
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| Posted: Wed Oct 27, 2021 1:25 pm Post subject: |
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| Nice solutions you guys! |
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