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VH+ 102521

 
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immpy



Joined: 06 May 2017
Posts: 470

PostPosted: Mon Oct 25, 2021 6:06 pm    Post subject: VH+ 102521 Reply with quote

Hello all, enjoy the puzzle...

Code:

+-------+-------+-------+
| 4 9 1 | . 2 . | . . . |
| . . . | 7 . . | . . 1 |
| . . . | . 5 . | 4 . . |
+-------+-------+-------+
| 5 . . | . 7 3 | 8 . 2 |
| 2 . . | . . . | . . 3 |
| 3 1 4 | 6 8 . | . . 7 |
+-------+-------+-------+
| . . 5 | . 4 . | . . . |
| 7 . . | . . 5 | . . . |
| . . . | . 3 . | 2 5 4 |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

cheers...immp
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Mogulmeister



Joined: 03 May 2007
Posts: 963

PostPosted: Tue Oct 26, 2021 9:51 am    Post subject: Reply with quote

After basics.

Code:
+--------------+----------------+----------------+
| 4   9   1    | 38   2   68    | 37   3678 5    |
| 68  5   23   | 7    69  4     | 39   2368 1    |
| 68  23  7    | 1389 5   1689  | 4    2368 689  |
+--------------+----------------+----------------+
| 5   6   9    | 4    7   3     | 8    1    2    |
| 2   7   8    | 5    19  19    | 6    4    3    |
| 3   1   4    | 6    8   2     | 5    9    7    |
+--------------+----------------+----------------+
| 19  23  5    | 1289 4   1689  | 1379 3678 689  |
| 7   4   23   | 1289 169 5     | 139  368  689  |
| 19  8   6    | 19   3   7     | 2    5    4    |
+--------------+----------------+----------------+


Thanks Immp!

I was tinkering with this and made a discovery.

If r2c7 = 3 then r2c3 =2 and puzzle solved. (four <23> chained together like a "spine")

-OR-

If r2c7 = 9 then stte and puzzle solved.(r2c3 = 2)

Whichever you choose for r2c7 we have a winner!


Last edited by Mogulmeister on Wed Oct 27, 2021 8:58 am; edited 1 time in total
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Clement



Joined: 24 Apr 2006
Posts: 1062
Location: Dar es Salaam Tanzania

PostPosted: Tue Oct 26, 2021 1:37 pm    Post subject: VH + 102521 Reply with quote

Code:

+------------------+-----------------------+-----------------------+
| 4      9      1  | 38       2       68   | 37       3678     5   |
| 68     5     c23 | 7        69      4    |c39       2368     1   |
| 68     23     7  | 1389     5       1689 | 4        2368     68-9|
+------------------+-----------------------+-----------------------+
| 5      6      9  | 4        7       3    | 8        1        2   |
| 2      7      8  | 5        19      19   | 6        4        3   |
| 3      1      4  | 6        8       2    | 5        9        7   |
+------------------+-----------------------+-----------------------+
| 19     23     5  | 1289     4       1689 | 1379     3678    a689 |
| 7      4     b23 | 1289     169     5    | 139     a368     a689 |
| 19     8      6  | 19       3       7    | 2        5        4   |
+------------------+-----------------------+-----------------------+

(9=6|83)b9p365 (3=2)r8c3 (2=39)r2c37 => - 9r3c9; stte
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Mogulmeister



Joined: 03 May 2007
Posts: 963

PostPosted: Tue Oct 26, 2021 2:22 pm    Post subject: Reply with quote

Another contradiction.

Using Clement's annotated grid we can also start in a different place (c)r2c7.

c(3-9)r2c7=(9-68)r3c9=a(68-9)r78c9=a(3-68)r8c8-b(3=2)r8c3-(2=3)r2c3-c(3=9)r2c7

Remove 9 in r2c7 and the loop contradicts it and puts the 9 back into r2c7.

R2c7 = 9.
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TomC



Joined: 30 Oct 2020
Posts: 143
Location: Wales

PostPosted: Tue Oct 26, 2021 5:44 pm    Post subject: Reply with quote

I used pincers on 3 in r1c4 and r2c7 to give -3 in r1c78
this sets r1c7 and r7c8 to 7
and this means -3 in r8c8 using the <23> in c3 otherwise no 3's in box 3
so r2c7=9

Bit of a scenic route here!
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Mogulmeister



Joined: 03 May 2007
Posts: 963

PostPosted: Wed Oct 27, 2021 9:02 am    Post subject: Reply with quote

Nice wing at the start there Tom to set the contradiction rolling.
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dongrave



Joined: 06 Mar 2014
Posts: 450

PostPosted: Wed Oct 27, 2021 1:25 pm    Post subject: Reply with quote

Nice solutions you guys!
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