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USA Today 15 May, 2015

 
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Mon Jun 01, 2015 10:00 pm    Post subject: USA Today 15 May, 2015 Reply with quote
So, here's a challenge:

No pencil marks?

Code:
Puzzle: USA051515
+-------+-------+-------+
| 4 . . | . 2 . | 6 . 8 |
| . . 5 | . 8 3 | . . . |
| . . . | . 4 . | . 5 9 |
+-------+-------+-------+
| . 5 7 | . 9 . | . . . |
| . . . | 4 3 6 | . . . |
| . . . | . 7 . | 3 1 . |
+-------+-------+-------+
| 7 4 . | . 1 . | . . . |
| . . . | 2 6 . | 7 . . |
| 1 . 9 | . 5 . | . . 3 |
+-------+-------+-------+

Keith
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Wed Jun 10, 2015 7:09 am    Post subject: Reply with quote
This is one of the toughest NAM (no advanced moves) puzzles I have seen. As has been noted, I am weird in that I think NAM puzzles should be done without pencil marks.

After singles:
Code:
+-------------------+-------------------+-------------------+
| 4     79    1     | 579   2     579   | 6     3     8     |
| 269   2679  5     | 1679  8     3     | 124   247   247   |
| 268   23678 2368  | 167   4     17    | 12    5     9     |
+-------------------+-------------------+-------------------+
| 3     5     7     | 18    9     128   | 248   2468  246   |
| 289   1     28    | 4     3     6     | 2589  2789  257   |
| 2689  2689  4     | 58    7     258   | 3     1     256   |
+-------------------+-------------------+-------------------+
| 7     4     268   | 3     1     89    | 2589  2689  256   |
| 5     38    38    | 2     6     489   | 7     489   1     |
| 1     268   9     | 78    5     478   | 248   2468  3     |
+-------------------+-------------------+-------------------+

Yes, you can do this without actually writing in the PMs. We are attacking C2.

There is a 38 pair in B7. R9C2 is 26.
Where is 9 in B6? There is a 28 pair in B4, so R6C2 is 269.
So, there is a pair 38 in C2, and R1C2 is 7 (because there is a triple 269 in C2).

Look at R2. R2C4 is not 9. R1C4 is 9 (in C4), and it is singles to the end.

Keith
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