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				|  Posted: Fri Aug 19, 2005 1:34 pm    Post subject: August 19th |   |  
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				| Need help... 
 Got to here:
 
 x83   192   45x
 95x   864   x23
 42x   xx5   x98
 
 598   4xx   x3x
 x1x   95x   x4x
 x4x   xx7   9x5
 
 1x9   5xx   x64
 865   x4x   xx9
 2x4   6x9   5xy
 
 
 The hint was to put 1 at "y" but I cant understand why that is clearly decided.
 
 Would be glad to get som help of "SuDoku-thinking"
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				|  Posted: Fri Aug 19, 2005 2:05 pm    Post subject: |   |  
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				| Other than going for y, after looking at the pattern, we can get these conclusions: 
 r8c8 can only be 1,7
 r9c8 can only be 1,7,8
 r9c9 can only be 1,7
 
 Since r8c8 and r9c9 can only be 1,7 we can eliminate these two numbers from r9c8, giving it the answer 8 in that cell.
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				|  Posted: Fri Aug 19, 2005 3:19 pm    Post subject: Ah... |   |  
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				| ...I see. Thanks a lot!!! 
 After staring at the numbers for too long I got stuck and saw no solution. Thanks for clearing things up for me!
 
 //Klas
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				|  Posted: Fri Aug 19, 2005 4:17 pm    Post subject: Re: August 19th |   |  
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				|  	  | Guest wrote: |  	  | Need help... 
 Got to here:
 
 x83   192   45x
 95x   864   x23
 42x   xx5   x98
 
 598   4xx   x3x
 x1x   95x   x4x
 x4x   xx7   9x5
 
 1x9   5xx   x64
 865   x4x   xx9
 2x4   6x9   5xy
 
 
 The hint was to put 1 at "y" but I cant understand why that is clearly decided.
 
 Would be glad to get som help of "SuDoku-thinking"
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 r9c9 has to be 1 or 7.
 
 c8 needs a 7. Since r6 already has a 7 (r6c6), that only leaves r8c8, r8c9.
 
 Therefore, r9c9 can't be a 7, so it must be 1.
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				|  Posted: Mon Aug 22, 2005 9:57 am    Post subject: True!!! |   |  
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				| Thanks for clearing that '1' for me as well. 
 Great!
 
 //Klas
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