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Assistenten x 16 February 2008

 
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arkietech



Joined: 31 Jul 2008
Posts: 1686
Location: Northwest Arkansas USA

PostPosted: Sat Jul 28, 2012 5:51 am    Post subject: Assistenten x 16 February 2008 Reply with quote

Code:

  *-----------*
 |31.|7..|...|
 |.5.|...|...|
 |...|.6.|.9.|
 |---+---+---|
 |..3|..5|...|
 |..6|...|7..|
 |...|1..|8..|
 |---+---+---|
 |.7.|.2.|...|
 |...|...|.3.|
 |...|..9|.58|
 *-----------*
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keith



Joined: 19 Sep 2005
Posts: 3136
Location: near Detroit, Michigan, USA

PostPosted: Sat Jul 28, 2012 6:22 am    Post subject: Reply with quote

After basics:
Code:
+-------------------+-------------------+-------------------+
| 3     1     29    | 7     59   *24    | 45    8     6     |
| 6     5     289   | 289   1389  12348 | 134   7     124   |
| 48   *24    7     | 258   6     1238  | 135   9     12    |
+-------------------+-------------------+-------------------+
| 7     48    3     | 6     48    5     | 19    2     19    |
| 1     89    6     | 289   389   238   | 7     4     5     |
| 45    249   25    | 1     49    7     | 8     6     3     |
+-------------------+-------------------+-------------------+
| 58    7     58    | 3     2     6     | 49    1     49    |
| 9     6     4     | 58    158   18    | 2     3     7     |
| 2     3     1     | 4     7     9     | 6     5     8     |
+-------------------+-------------------+-------------------+

R3C2 and R1C6 are pincers on 2. Don't ask me why.

Otherwise, a short chain (extended XY-wing) solves it.

Keith
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arkietech



Joined: 31 Jul 2008
Posts: 1686
Location: Northwest Arkansas USA

PostPosted: Sat Jul 28, 2012 10:54 am    Post subject: Reply with quote

I used the 9's
Code:
 *--------------------------------------------------------------------*
 | 3      1     a29     | 7      5-9    24     | 45     8      6      |
 | 6      5      289    | 289    1389   12348  | 134    7      124    |
 | 48     24     7      | 258    6      1238   | 135    9      12     |
 |----------------------+----------------------+----------------------|
 | 7      48     3      | 6      48     5      | 19     2      19     |
 | 1      89     6      | 289    389    238    | 7      4      5      |
 | 45    c249   b25     | 1     d49     7      | 8      6      3      |
 |----------------------+----------------------+----------------------|
 | 58     7      58     | 3      2      6      | 49     1      49     |
 | 9      6      4      | 58     158    18     | 2      3      7      |
 | 2      3      1      | 4      7      9      | 6      5      8      |
 *--------------------------------------------------------------------*
 m-wing
(9=2)r1c3-r6c3=(2-9)r6c2=9r6c5 => -9r1c5; stte

if r1c3 is not a 9 then r6c5 ia a 9
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tlanglet



Joined: 17 Oct 2007
Posts: 2461
Location: Northern California Foothills

PostPosted: Sat Jul 28, 2012 1:33 pm    Post subject: Reply with quote

keith wrote:
After basics:
Code:
+-------------------+-------------------+-------------------+
| 3     1     29    | 7     59   *24    | 45    8     6     |
| 6     5     289   | 289   1389  12348 | 134   7     124   |
| 48   *24    7     | 258   6     1238  | 135   9     12    |
+-------------------+-------------------+-------------------+
| 7     48    3     | 6     48    5     | 19    2     19    |
| 1     89    6     | 289   389   238   | 7     4     5     |
| 45    249   25    | 1     49    7     | 8     6     3     |
+-------------------+-------------------+-------------------+
| 58    7     58    | 3     2     6     | 49    1     49    |
| 9     6     4     | 58    158   18    | 2     3     7     |
| 2     3     1     | 4     7     9     | 6     5     8     |
+-------------------+-------------------+-------------------+

R3C2 and R1C6 are pincers on 2. Don't ask me why.

Keith

One explanation is a w-wing(24) with a long path on (4) as the SL which is in box3
(4)r1c7-(4=2)r1c6
(4)r2c79-(4=5=9)r1c75-(9=4)r6c5-r4c5=r4c2-(4=2)r3c2; -2r1c3,r3c46

Ted
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tlanglet



Joined: 17 Oct 2007
Posts: 2461
Location: Northern California Foothills

PostPosted: Sat Jul 28, 2012 1:36 pm    Post subject: Reply with quote

My first solution was a messy axy-wing(24-9)r3c2+r1c3|r6c2 with fin (4)r6c2
The xy-wing gives pincers (9) in r1c3 & r6c2; however (9)r6c2-(9=4)r6c5-r4c5=r4c2-(4=2)r3c2-(2=9)r1c3.
Finally the fin gives (4)r6c2-(4=5=2)r6c13-(2=9)r1c3
Thus, all paths lead to r1c3=9 to complete the puzzle.

At that point I realized that multiple short chains were possible using similar logic paths.

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5061
Location: Rochester, NY, USA

PostPosted: Sat Jul 28, 2012 5:53 pm    Post subject: Reply with quote

Four-cell XY-Chain. R6c5=4--->r1c3=9; r1c5<>9.
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