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Puzzle 11/07/19: ~ XY
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susume



Joined: 13 May 2011
Posts: 36
Location: Southeastern US

PostPosted: Fri Jul 22, 2011 5:00 pm    Post subject: Reply with quote

I've only just recently added BUG to my repertoire, so not surprising I missed something basic. Thanks for the reminder.

I googled "quantum" in the sudoku context but didn't find anything introductory level; any pointers to learn more about it?
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Fri Jul 22, 2011 5:40 pm    Post subject: Reply with quote

Susume, I would offer some input - but according to ronk I have it wrong anyway! So maybe he will chime in...

I saw your move as creating a naked pair (17)r78c4 and so eliminating r6c4<>7=8. But also there is the strong link on 8 so just ignore what I said!
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daj95376



Joined: 23 Aug 2008
Posts: 3855

PostPosted: Fri Jul 22, 2011 6:38 pm    Post subject: Reply with quote

I'm even further confused. I thought it was a BUG+2.

FWIW, I would have written:

Code:
(4*=17)r8c5,r7c4 - (17=48)r8c4; *BUG  =>  r8c5=4
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ronk



Joined: 07 May 2006
Posts: 397

PostPosted: Fri Jul 22, 2011 7:30 pm    Post subject: Reply with quote

daj95376 wrote:
I'm even further confused. I thought it was a BUG+2.

It is, I cut & pasted without reading closely. Will edit my post and address the quantum term when I get to a real PC. Haven't learned how to do much on this iPad yet.

daj95376 wrote:

Code:
(4*=17)r8c5,r7c4 - (17=48)r8c4; *BUG  =>  r8c5=4

I don't understand that.
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Marty R.



Joined: 12 Feb 2006
Posts: 5160
Location: Rochester, NY, USA

PostPosted: Fri Jul 22, 2011 9:36 pm    Post subject: Reply with quote

Quote:
I'm even further confused. I thought it was a BUG+2.

I'm not sure I should even join this discussion, but it sounds like the "X" in BUG+X refers to the number of cells only, even though there are three possibilities with one cell being a quad. Doesn't calling this a BUG+2 need some sort of qualifier, sort of like a BUG+2 with a man in motion?

Just trying to guess at the quantum thing. I wonder if it just means that it needs to be one more cell than the number of candidates, i.e., three cells for a quantum pair and four for a triple.

If these are the roof cells of a UR and one other cell in the same house, do we have a quantum pair? 126-127-67.
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daj95376



Joined: 23 Aug 2008
Posts: 3855

PostPosted: Fri Jul 22, 2011 10:38 pm    Post subject: Reply with quote

ronk wrote:
daj95376 wrote:

Code:
(4*=17)r8c5,r7c4 - (17=48)r8c4; *BUG  =>  r8c5=4

I don't understand that.

Yeah, it probably is a stretch. I was trying to indicate that r8c5<>4 leads to r8c4=48 and, with memory of the initial elimination, we could deduce that a BUG remains. Since this is a contradiction, we can conclude that r8c5=4.

Regards, Danny
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