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Jan 3 VH

 
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Clement



Joined: 24 Apr 2006
Posts: 1110
Location: Dar es Salaam Tanzania
PostPosted: Sun Jan 02, 2011 10:07 pm    Post subject: Jan 3 VH Reply with quote
XY-Wing 56 57 67 pivoted in r4c2 eliminating 6 in r8c3 solves it.
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kuskey



Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH
PostPosted: Mon Jan 03, 2011 6:17 am    Post subject: Jan 3 VH Reply with quote
If things look familiar, try Dec. 20. Besides Clement's solution, look for some of the following:

1) 3 more x-wings on 567
2) 4 w-wings on 56
3) 4 w-wings on 67

at that point, my eyeballs caged permanently so there may be more.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Mon Jan 03, 2011 4:39 pm    Post subject: Reply with quote
There were a couple of ways to work the 37 UR in boxes 36 plus at least one XY-Chain.
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kuskey



Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH
PostPosted: Tue Jan 04, 2011 12:01 am    Post subject: Jan 3 VH Reply with quote
Marty, would you be so kind as to give the explanation of your 37 UR solution. I'm trying to learn the more difficult UR techniques and this sure looks like one. Is it a type 6?

thanks
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Tue Jan 04, 2011 1:07 am    Post subject: Re: Jan 3 VH Reply with quote
kuskey wrote:
Marty, would you be so kind as to give the explanation of your 37 UR solution. I'm trying to learn the more difficult UR techniques and this sure looks like one. Is it a type 6?

thanks

No, it isn't a type anything, just a potential UR or DP.

Code:

+-----------+---------+-------------+
| 9   2  4  | 56 8 1  | 567 367 367 |
| 8   3  7  | 56 9 4  | 256 26  1   |
| 56  56 1  | 7  3 2  | 8   9   4   |
+-----------+---------+-------------+
| 4   57 2  | 8  6 9  | 1   357 357 |
| 1   9  56 | 2  7 3  | 4   8   56  |
| 67  8  3  | 1  4 5  | 267 267 9   |
+-----------+---------+-------------+
| 2   4  8  | 3  1 67 | 9   567 567 |
| 567 1  56 | 9  2 67 | 3   4   8   |
| 3   67 9  | 4  5 8  | 67  1   2   |
+-----------+---------+-------------+

Play this puzzle online at the Daily Sudoku site

Either r2c8 or 9 must be 6 or r4c8 or 9 must be 5. Testing both possibilities I found a common outcome, that is, r78c6=67. Or taking a different path, 5s in r4c8 or 9 leads to an invalidity, forcing r5c9=5.

P.S. I erred above is saying that r78c6=67 was a common outcome.
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