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		| David Bryant 
 
 
 Joined: 29 Jul 2005
 Posts: 559
 Location: Denver, Colorado
 
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				|  Posted: Mon Feb 27, 2006 7:32 pm    Post subject: Another "coloring" example |   |  
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				|  	  | Keith wrote: |  	  | Thank you. These colors, chains and cycles are coming into focus for me. | 
 Today's "Nightmare" puzzle (27 Feb 2006) offers an excellent opportunity for "coloring" logic.
 
  	  | Code: |  	  | .1....6.. .8.2.4...
 6...3...8
 .5......1
 ..6.9.2..
 7......8.
 4...1...3
 ...8.3.5.
 ..9....7.
 | 
 1. Naked pair {3, 4} in row 5.
 2. Hidden pair {5, 8} in r7c3 & r9c1; r9c2 = 3.
 3. Naked pair resolved -- r5c3 = 4, r5c8 = 3.
 4. r9c7 = 1 (unique horizontal)
 5. r9c1 = 8 (unique horizontal); r7c3 = 5 (sole candidate)
 6. r5c1 = 1 (sole candidate); r7c1 = 2 (sole candidate); r7c3 = 1 (sole candidate)
 7. {6, 7} pair in r7c2 & r8c2.
 8. r4c3 = 8 (unique vertical); r7c7 = 8 (unique horizontal)
 9. r1c5 = 8 (unique vertical); r5c6 = 8 (unique vertical)
 10. r2c8 = 1 (unique horizontal)
 11. The "2" in row 6 lies in middle left 3x3 box.
 12. r2c7 = 3 (unique horizontal); r2c3 = 7 (sole candidate); r2c5 = 6 (sole candidate)
 13. Naked triplet {2, 4, 9} in row 3.
 14. The "9" in row 1 lies in top center 3x3 box.
 15. Coloring on "5" in row 5 and column 7 reveals r3c4 <> 5
 16. X-Wing on "9" in columns 4 & 6 -- r7c8 <> 9.
 
 At this point we're ready for the final push -- the grid looks like this.
 
  	  | Code: |  	  | 35     1    234   579    8    579    6    24   2457 59+    8     7     2     6     4     3     1    59-
 6    29-   24    17     3    157   57    249+   8
 39-    5     8   3467   247   276   479   469-   1
 1     4     6    57     9     8     2     3    57
 7    29+   23   13456  45    156   459(-) 8   4569*
 4    67     5    679    1   2679    8    26     3
 2    67     1     8    47     3    49(-)  5    469(+)
 8     3     9    456   245   256    1     7    246
 | 
 We have a binary chain in the "9"s, marked +/- above. First we observe that the "9" at r6c9 can be eliminated because there's a "+" at r6c2 and a "-" at r2c9. With that "9" out of the way we can mark another "+" at r8c9, and two more "-9"s, at r6c7 and r8c7.
 
 But now we have two "-9"s in the same column (7), and also two "-9"s in the same row (4). We conclude that "-" is not 9, and "+" is, solving for ten cells simultaneously and breaking the puzzle wide open.  dcb
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