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ClaireB
Joined: 16 Jun 2010
Posts: 4
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 Posted: Thu Jul 01, 2010 3:27 am Post subject: Daily Sudoku 1 July 10 |
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Help I am new to this.
How is the 5 eliminated from R2C2 to leave a 9 ?
This seems to be the key to the whole puzzle.
Any advice appreciated 
Thanks Claire
+---------------+--------------+-------------+
| 357 6 457 | 9 1 25 | 48 238 245 |
| 2 59 8 | 3 45 6 | 1 7 459 |
| 3579 1 457 | 457 2457 8 | 49 23 6 |
+---------------+--------------+-------------+
| 1 8 3 | 2 6 4 | 5 9 7 |
| 4 2579 257 | 57 8 59 | 3 6 1 |
| 579 579 6 | 1 579 3 | 2 4 8 |
+---------------+--------------+-------------+
| 6 237 1 | 8 2349 29 | 479 5 249 |
| 57 4 9 | 6 25 1 | 78 28 3 |
| 8 235 25 | 45 23459 7 | 6 1 249 |
+---------------+--------------+-------------+ |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Jul 01, 2010 3:43 am Post subject: Re: Daily Sudoku 1 July 10 |
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Here's an aligned grid:
| Code: | +---------------+--------------+-------------+
| 357 6 457 | 9 1 25 | 48 238 245 |
| 2 59 8 | 3 45 6 | 1 7 459 |
| 3579 1 457 | 457 2457 8 | 49 23 6 |
+---------------+--------------+-------------+
| 1 8 3 | 2 6 4 | 5 9 7 |
| 4 2579 257 | 57 8 59 | 3 6 1 |
| 579 579 6 | 1 579 3 | 2 4 8 |
+---------------+--------------+-------------+
| 6 237 1 | 8 2349 29 | 479 5 249 |
| 57 4 9 | 6 25 1 | 78 28 3 |
| 8 235 25 | 45 23459 7 | 6 1 249 |
+---------------+--------------+-------------+ |
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nataraj
Joined: 03 Aug 2007
Posts: 1048
Location: near Vienna, Austria
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| Posted: Thu Jul 01, 2010 9:40 am Post subject: Re: Daily Sudoku 1 July 10 |
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| ClaireB wrote: |
How is the 5 eliminated from R2C2 to leave a 9 ?
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Claire,
the "5" is not eliminated, but rather the "9" is chosen...
First, the "3"s in r3c1 and r3c3 must be eliminated (the "3"s in box 2 are all in row 3). Then we are done with basics.
There is an xy-wing 49-45-59 (r3c7,r3c3,r2c2) that removes 9 from cells r3c1,r2c9 which leaves 9 in r2c2 as a hidden single (there is no other 9 in box 1, nor in row 2) |
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Kdelle
Joined: 20 Mar 2008
Posts: 59
Location: Hudson, NH
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| Posted: Thu Jul 01, 2010 4:35 pm Post subject: Re: Daily Sudoku 1 July 10 |
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| nataraj wrote: | | ClaireB wrote: |
How is the 5 eliminated from R2C2 to leave a 9 ?
|
Claire,
the "5" is not eliminated, but rather the "9" is chosen...
First, the "3"s in r3c1 and r3c3 must be eliminated (the "3"s in box 2 are all in row 3). Then we are done with basics.
There is an xy-wing 49-45-59 (r3c7,r3c3,r2c2) that removes 9 from cells r3c1,r2c9 which leaves 9 in r2c2 as a hidden single (there is no other 9 in box 1, nor in row 2) |
Claire.....I'm pretty sure he means 7s in box 2 eliminate 7s in Row3
Kathy |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Thu Jul 01, 2010 10:17 pm Post subject: |
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After basics: | Code: | +-------------------+-------------------+-------------------+
| 357 6 457 | 9 1 25 | 48 238 245 |
| 2 59 8 | 3 45 6 | 1 7 459 |
| 359 1 45 | 457 2457 8 | 49 23 6 |
+-------------------+-------------------+-------------------+
| 1 8 3 | 2 6 4 | 5 9 7 |
| 4 2579 257 | 57 8 59 | 3 6 1 |
| 579 579 6 | 1 579 3 | 2 4 8 |
+-------------------+-------------------+-------------------+
| 6 237 1 | 8 2349 29 | 479 5 249 |
| 57 4 9 | 6 25 1 | 78 28 3 |
| 8 235 25 | 45 23459 7 | 6 1 249 |
+-------------------+-------------------+-------------------+ |
A 45-9 XY-wing does it in one step.
Keith |
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