View previous topic :: View next topic 
Author 
Message 
TPM
Joined: 13 Jun 2006 Posts: 4 Location: Gauteng, South Africa

Posted: Tue Sep 12, 2006 4:02 pm Post subject: September 12 Very hard 


Just when I thougt I'm getting the feel for this thing, pops one out of hell(if there is such a place).
Did the basic elimination until I got and Xwing on 5's in rows 3&7 cols 2 & 7. So, far I have the following:
7 {2369} {569} {238} {245} {248} {345} 1 {46}
4 {23} {15} {1237} {257} 6 {35} 9 8
{136} {356} 8 {13} 9 {14} 7 {3456} 2
5 {78} 3 6 1 {27} {248} {248} 9
{69} {6789} {679} 4 {27} 3 1 {28} 5
2 1 4 9 8 5 6 7 3
8 {57} 2 {17} 3 {147} 9 {456} {46}
{1369} {369} {169} 5 {246} {2489} {2348} {2348} 7
{369} 4 {57} {278} {267} {2789} {2358} {238} 1
Asking for a hint gives me a 4 in r3c6. can't see why. Am I missing something? 

Back to top 


blackwood
Joined: 12 Sep 2006 Posts: 4 Location: Lehi, Utah, USA

Posted: Tue Sep 12, 2006 5:51 pm Post subject: 


There is a hidden set {5,6} in R3C8 and R7C8. This then leaves the 4 in R3C6 as the only 4 for R3. (A pinned square)
Blackwood 

Back to top 


Marty R.
Joined: 12 Feb 2006 Posts: 5508 Location: Rochester, NY, USA

Posted: Tue Sep 12, 2006 9:29 pm Post subject: 


Just to say the same thing as Blackwood did, except a little differently. In rows 4, 5, 8 and 9 in col. 8 there is a naked quad of 2348. When you make the eliminations from this quad, the 56 goes from a hidden to naked set.
I personally do not have the eye to spot hidden sets, but can generally spot the complementary naked sets. 

Back to top 


George Woods
Joined: 28 Mar 2006 Posts: 275 Location: Dorset UK

Posted: Tue Sep 12, 2006 11:24 pm Post subject: 


I solved this one by what seems to be like an XY wing. r7c6 cannot hold 4 'cos the 4 propagated by the 46 in col9 would make for a 4 in r3c6 which is of course a no no so there is now a 17 pair in row 7 allowing progress and a solution to be obtained.
Trying to understand the analysis above. I found a diificulty with the original contents of r8c8 and r9c8 (given as 2348 and 238) I make these two 23468 and 23568 so where have I missed the obvious? 

Back to top 


Marty R.
Joined: 12 Feb 2006 Posts: 5508 Location: Rochester, NY, USA

Posted: Wed Sep 13, 2006 4:55 am Post subject: 


Just to give yet one more illustration of how many different ways there are to solve many puzzles, on this one there were two Finned XWings, an XWing and then strong links (aka fork, aka skyscraper) on "4" opened it up. 

Back to top 


TPM
Joined: 13 Jun 2006 Posts: 4 Location: Gauteng, South Africa

Posted: Wed Sep 13, 2006 5:23 am Post subject: 


Okay ta everybody. I should have seen the hidden 56 in 8. Just had one of those bad days. However, I've learned now about a quad. I have never used it before as I did not understand it.
George, you cannot have a 6 in r8c8 as the 6 in r7 can only be in col 8 or col 9, hence eliminating any other 6's in the last box. alternatively, looking at the bottom 3 boxes, you can see that the 6 in the first 2 boxes is in rows 8 & 9 hence forcing the 6 in the last box to be in row 7 only.
The 5 is eliminated by the Xwing on the 5's in rows 3&7 cols 2&8. Hope this helps. 

Back to top 


George Woods
Joined: 28 Mar 2006 Posts: 275 Location: Dorset UK

Posted: Wed Sep 13, 2006 7:56 am Post subject: 


Marty R. wrote:  Just to give yet one more illustration of how many different ways there are to solve many puzzles, on this one there were two Finned XWings, an XWing and then strong links (aka fork, aka skyscraper) on "4" opened it up. 
So how do you describe my method? (I spotted the "strong" link between r7c6 to r7c9 to r1c9 to r3c6 with the last one in my terminology a negative one i.e normally a 4 in one cell denies the 4 in the "strongly" linked cell but here a 4 in r1c9 forces the 4 in r3c6  so in my terminology we have a chain but with one negative which makes for a nonsense) what I can't do (ignorance) is classify it a s a skyscraper or finned Xwing  never having taken a course in sudoku solving!
And whats more this leads to a solution directly  never putting more than a "double" candiate for a cell! and no need for the XWing 

Back to top 


Marty R.
Joined: 12 Feb 2006 Posts: 5508 Location: Rochester, NY, USA

Posted: Wed Sep 13, 2006 3:50 pm Post subject: 


Quote:  So how do you describe my method? 
I don't have an answer; maybe one of the more creative types can describe it. But whatever, if it's based on logic, that's the name of the game.
Quote:  what I can't do (ignorance) is classify it a s a skyscraper or finned Xwing  never having taken a course in sudoku solving! 
I've taken that course. It consisted of scouring web sites for basic and advanced techniques and printing them out to build up a reference base. Also on this forum, when someone used a technique that wasn't familiar to me, I asked about it and printed out the answer for my reference files.
I've now been into this nonsense long enough that I don't have to refer to that material very often, but it was a great aid in learning. The technique I mentioned aboveFinned XWingwas one I didn't see on the web sites and learned from this forum. I suspect with my questions that I may have been considered a pest at times, but asking is the way I learn. 

Back to top 


TKiel
Joined: 22 Feb 2006 Posts: 292 Location: Kalamazoo, MI

Posted: Wed Sep 13, 2006 10:09 pm Post subject: 


George Woods wrote:  So how do you describe my method? 
It's known either as a 'turbot fish' or more generally as multicolouring.
The grid probably looks something like this:
Code: 
**
 7 23569 569  238 245 248  3458 1 46B 
 4 235 15  12378 257 6  358 9 58 
 136 356 8  13 9 14a  7 3456A 2 
++
 5 78 3  6 1 27  248 248 9 
 69 6789 679  4 27 3  1 258 58 
 2 1 4  9 8 5  6 7 3 
++
 8 567 2  17 3 147  9 456 46b 
 1369 369 169  5 246 12489  2348 23468 7 
 369 4 5679  278 267 2789  2358 23568 1 
**

The cells in row 3 are conjugate (strong links). The cells in column 9 are also. The cells with capitals both can't be 4 so one or both of the small lettered cells must be. Any cell that 'sees' both of a and b can't be a 4.
Last edited by TKiel on Thu Sep 14, 2006 12:10 am; edited 1 time in total 

Back to top 


CT Yankee
Joined: 17 Jul 2006 Posts: 11 Location: New England

Posted: Wed Sep 13, 2006 10:59 pm Post subject: 


I solved this one using basic techniques, and then a Swordfish on the 5s. This is the very first time I have ever had to use a Swordfish! I've been aware of the technique for a long time, and I always look for it, but this is the very first time it ever really stood out as a way forward when I couldn't spot anything else. Most of the time I suspect I've been using other methods that supercede fishing expeditions  that's the only explanation I have for why I never seem to need a technique that everyone else considers indispensable. 

Back to top 


TKiel
Joined: 22 Feb 2006 Posts: 292 Location: Kalamazoo, MI

Posted: Thu Sep 14, 2006 12:59 am Post subject: 


CT Yankee,
The Xwing and the Swordfish are complementary and basically make the same exclusions. Many fish are accompanied by other fish. It makes sense when you think about it. If there are 5 rows & columns not solved for a particular number and 2 of those row & columns form an Xwing, the other cells must form a Swordfish.
As to why you've never had to use a Swordfish before I don't have an answer. Maybe you need to start doing easier puzzles. 

Back to top 


riderdude
Joined: 04 Jun 2006 Posts: 9 Location: Mass

Posted: Fri Sep 15, 2006 3:07 am Post subject: 


TPM wrote:  George, you cannot have a 6 in r8c8 as the 6 in r7 can only be in col 8 or col 9 
sorry, i'm with George. why can't there be a 6 in r2c7? 

Back to top 


TKiel
Joined: 22 Feb 2006 Posts: 292 Location: Kalamazoo, MI

Posted: Fri Sep 15, 2006 10:38 am Post subject: 


riderdude wrote:  sorry, i'm with George. why can't there be a 6 in r2c7? 
Not sure if the cell location is just a misprint, but r2c6 is a 6. 

Back to top 


riderdude
Joined: 04 Jun 2006 Posts: 9 Location: Mass

Posted: Fri Sep 15, 2006 1:14 pm Post subject: 


TKiel wrote:  Not sure if the cell location is just a misprint, but r2c6 is a 6. 
doh
yes, typo. i meant r7c2. if i can get rid of the 6 there, i can get rid of other 6s in box 9. then the 4 in r3c8 is apparent. i was at pretty much the same place as TPM when i got stuck, too.


Back to top 


David Bryant
Joined: 29 Jul 2005 Posts: 559 Location: Denver, Colorado

Posted: Fri Sep 15, 2006 6:35 pm Post subject: Catching swordfish 


CTYankee wrote:  This is the very first time I have ever had to use a Swordfish! ... 
There's a very cute example of a swordfish in the archives over at Ruud's excellent web site.
Oh  it's on the "8"s, in columns. And it's a real swordfish  the complement is a "jellyfish". There's also a "finned swordfish" (on a different digit) after you find the straightforward one. Better yet, finding those two finny friends doesn't solve the puzzle  there's still a lot of work to do after you've reeled in your catch! dcb 

Back to top 


Marty R.
Joined: 12 Feb 2006 Posts: 5508 Location: Rochester, NY, USA

Posted: Fri Sep 15, 2006 9:00 pm Post subject: 


Quote:  And it's a real swordfish  the complement is a "jellyfish". 
David, could you elaborate? I was under the impression that complementary fish added up to nine, whereas a swordfish + jellyfish = seven. 

Back to top 


David Bryant
Joined: 29 Jul 2005 Posts: 559 Location: Denver, Colorado

Posted: Fri Sep 15, 2006 9:27 pm Post subject: Fish & complements 


Marty R wrote:  was under the impression that complementary fish added up to nine ... 
Hi, Marty!
The formula you need is
order(fish) + order(fishy complement) + # of digits "x" already resolved = 9
So if no "5"s (for instance) have yet been placed in the puzzle, and there's a "swordfish" on the "5"s, then the complementary fish will be of order 6. (It's a little more complicated than that ... for instance, the set of 9 columns and rows might be broken up into 3 distinct swordfish. Or there might be the one swordfish, one jellyfish, and one XWing. Or one swordfish and 3 XWings, etc.) But if 2 "5"s have already been placed in the puzzle, then the complement of the swordfish will be of order 4 (ie, a jellyfish) because 3 + 4 + 2 = 9.
In the "Nightmare" puzzle I was talking about two "8"s have been given as initial clues. So there are only 7 columns & rows that need an "8", and those 7 break up into a swordfish (on columns) and a jellyfish (on rows). Does that make sense? dcb 

Back to top 


Marty R.
Joined: 12 Feb 2006 Posts: 5508 Location: Rochester, NY, USA

Posted: Sat Sep 16, 2006 5:03 am Post subject: 


Quote:  Does that make sense? 
Yes, up to a point. I understand why I was wrong about the complements adding up to nine, but I'll have to read this a few more times to digest it fully.
Thanks David. 

Back to top 


George Woods
Joined: 28 Mar 2006 Posts: 275 Location: Dorset UK

Posted: Sat Sep 16, 2006 11:28 am Post subject: 


riderdude wrote:  TKiel wrote:  Not sure if the cell location is just a misprint, but r2c6 is a 6. 
doh
yes, typo. i meant r7c2. if i can get rid of the 6 there, i can get rid of other 6s in box 9. then the 4 in r3c8 is apparent. i was at pretty much the same place as TPM when i got stuck, too.

Look at the 57 attacks on box 7  your cell has to be 57 hence no 6!
I suppose this is described a s a "hidden pair" 57 in box 7 

Back to top 


keith
Joined: 19 Sep 2005 Posts: 3260 Location: near Detroit, Michigan, USA

Posted: Sat Sep 16, 2006 8:15 pm Post subject: Missing a fish? 


David wrote:
Quote:  order(fish) + order(fishy complement) + # of digits "x" already resolved = 9

Except, in this case
Code:  ++++
 7 23569 569  238 245 248  3458 1 46 
 4 235 15  12378 257 6  358 9 58 
 136 356 8  13 9 14  7 3456 2 
++++
 5 78 3  6 1 27  248 248 9 
 69 6789 679  4 27 3  1 258 58 
 2 1 4  9 8 5  6 7 3 
++++
 8 57 2  17 3 147  9 456 46 
 1369 369 169  5 246 2489  2348 2348 7 
 369 4 57  278 267 2789  2358 2358 1 
++++

Three (3) of the 5's are solved, and there is supposedly an Xwing (2) and a complementary swordfish (3). Adds up to 8.
Even more fishy, the eliminations of the swordfish and the Xwing are not the same.
Here is the Xwing:
Here is the Swordfish:
In fact, the Xwing is part of a second Swordfish. Here it is:
Keith 

Back to top 


