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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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 Posted: Sun Jun 26, 2011 12:35 am Post subject: Jun 26 VH |
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A long process for me:-
1) A kite originating from BOX 7 sets r1c6<>9 opens an
2) XYZ-Wing 14 147 47 with apex in r1c6 sets r1c5<>4
3) UR in 34 removes 4 in r46c2 which opens another kite in 4 originating from BOX 7 setting r1c6<>4 this leads to
4) W-Wing 48 with strong link 4 in row 1 setting r7c1<>8 which finally solves it. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Jun 26, 2011 12:58 am Post subject: |
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Like Clement, I didn't have an easy time. This is my post-basics grid:
| Code: |
+--------------+---------------+------------+
| 149 14 8 | 5 4679 1479 | 3 2 67 |
| 2 5 6 | 47 3 8 | 147 9 17 |
| 3 7 149 | 2 469 149 | 48 5 68 |
+--------------+---------------+------------+
| 6 1348 2 | 478 5 47 | 9 34 178 |
| 48 9 5 | 1 478 3 | 78 6 2 |
| 148 1348 7 | 9 2 6 | 18 34 5 |
+--------------+---------------+------------+
| 189 6 19 | 3 89 5 | 2 7 4 |
| 7 2 49 | 6 1 49 | 5 8 3 |
| 5 48 3 | 478 478 2 | 6 1 9 |
+--------------+---------------+------------+
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Play this puzzle online at the Daily Sudoku site
I couldn't find any of the VH moves other than an apparently useless 148 XYZ-Wing. I used overlapping ERs on 49 to remove those two numbers from r1c6, setting up an XY-Wing (174) which removed 4 from r1c5 and from r3c3 after a pincer transport. The 34 UR, originally a Type 4, is now a Type 2 and finishes it off. |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sun Jun 26, 2011 1:51 am Post subject: |
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| Quote: | Why is the XYZ-wing useless? It eliminates 8 in R6C2. It sets up an X-wing that solves the puzzle.
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Keith |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sun Jun 26, 2011 2:21 am Post subject: |
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Overkill of course, but ...
An M-wing nails it. After basics: | Code: | +----------------+----------------+----------------+
| 149 14a 8 | 5 -4679 1-479| 3 2 67 |
| 2 5 6 | 47e 3 8 | 147d 9 17 |
| 3 7 149 | 2 469 149 | 48 5 68 |
+----------------+----------------+----------------+
| 6 1348 2 | 478 5 47 | 9 34 178c |
| 48 9 5 | 1 478 3 | 78 6 2 |
| 148b 1348 7 | 9 2 6 | 18 34 5 |
+----------------+----------------+----------------+
| 189 6 19 | 3 89 5 | 2 7 4 |
| 7 2 49 | 6 1 49 | 5 8 3 |
| 5 48 3 | 478 478 2 | 6 1 9 |
+----------------+----------------+----------------+ |
1 in a forces 1 in b, c, d. Not 1 in d forces 4 in e, making the eliminations shown.
Keith |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Jun 26, 2011 3:41 am Post subject: |
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| keith wrote: | | Quote: | Why is the XYZ-wing useless? It eliminates 8 in R6C2. It sets up an X-wing that solves the puzzle.
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Keith |
It obviously isn't useless, but my analysis was. I just eyeballed it for apparent help and didn't carry it as far as an X-Wing search. |
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prakash
Joined: 02 Jan 2008
Posts: 67
Location: New Jersey, USA
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| Posted: Sun Jun 26, 2011 3:55 pm Post subject: |
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Like Clement I used the kite and the XYZ wing, but, the third step for me was a finned X wing in 4. This solved th puzzle.
- PJ |
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George Woods
Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK
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| Posted: Sun Jun 26, 2011 4:18 pm Post subject: don't know whether it waS an M wing but |
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| I used the 14 in r1c2 (first doublet in the grid) If 1 then r4c9 is 1 directly and if not 1 than the 8s in boxes 7,8 and 5 fall out immediately and lead to r4c9 <>8 hence r3c9=8 AND A SOLUTION . I thought this was an act of desperation but if I can call it an M wing then great! |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Mon Jun 27, 2011 5:20 pm Post subject: |
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| I used ERs to remove the 4 and 9 from R1C6 then an xy wing on 147. |
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