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AZ Matt
Joined: 03 Nov 2005 Posts: 63 Location: Hiding under my desk in Phoenix AZ USA
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Posted: Mon Aug 14, 2006 7:00 pm Post subject: UR Type 5??? |
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Ran across this today, and I thought I'd get your take on it:
Code: | 8 6 4 1 7 2 9 3 5
3 5 27 9 4 6 278 1 28
9 17 127 3 5 8 27 6 4 |
If r3c2 = <1> ==> r2c3, r3c3 = <27>
If r3c2 = <7> ==> r2c3 = <2> ==> r3c3 = <7>
In either case (based on UR theory in the first case), r2c7 cannot = <2>, and the 2 can be eliminated as a candidate for that cell.
Using that same logic, you can also eliminate the 7 as a candidate from r3c3.
Unfortunately, neither of those tidbits solved the puzzle (it's today's Brian Basher's Super Hard, turned ninety degrees so it is easier to see the UR), but I thought it was interesting.
I assume this isn't new, but I haven't run across it before, and it seems like it would happen fairly often and occasionally be useful.
Any thoughts? |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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AZ Matt
Joined: 03 Nov 2005 Posts: 63 Location: Hiding under my desk in Phoenix AZ USA
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Posted: Mon Aug 14, 2006 8:54 pm Post subject: UR 5 |
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It is today's (August 14) Super Hard at brainbashers.com. I didn't post it because it didn't help solve the puzzle, and I finally found an xy-wing that brought the puzzle down all at once, but here it is:
006402900
040080050
900050004
400708001
068000540
700503002
600030009
070090010
009607400
It is in boxes 3 and 9.
It seems like it wouldn't be that rare to find that pattern in two boxes with trips remaining, but I certainly never looked for it before. I suppos some would argue that it is like forcing chains in a UR format. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Mon Aug 14, 2006 10:07 pm Post subject: Well, not Type 5 |
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AZ,
I was incorrect, this is not a Type 5 (which is a diagonal form of Type 2). It is a Type 7 or greater, look at:
http://www.sudoku.com/forums/viewtopic.php?t=4088
Type 6 is a UR on an X-wing, see
http://www.sudoku.com/forums/viewtopic.php?t=3709&start=0
The classifications into types do not much matter to me. Rather, it is the idea of blending UR's with strong links. You say:
Quote: | I suppos some would argue that it is like forcing chains in a UR format. |
which I think is exactly correct. The neat thing is, the UR gives you set of cells to look for a short chain, and the criterion is to avoid the non-unique pattern.
By the way, I get to this point:
Code: | +-------------+-------------+-------------+
| 15 15 6 | 4 7 2 | 9 3 8 |
| 2 4 37 | 139 8 19 | 17 5 6 |
| 9 8 37 | 13 5 6 | 127 27 4 |
+-------------+-------------+-------------+
| 4 25 25 | 7 6 8 | 3 9 1 |
| 3 6 8 | 129 12 19 | 5 4 7 |
| 7 9 1 | 5 4 3 | 8 6 2 |
+-------------+-------------+-------------+
| 6 125 245 | 128 3 45 | 27 278 9 |
| 58 7 245 | 28 9 45 | 6 1 3 |
| 18 3 9 | 6 12 7 | 4 28 5 |
+-------------+-------------+-------------+ |
Did you notice FOUR UR's? There is a Type 4 R25C46, a Type 2 R78C36, yours R37C78, and another R47C23. You don't need all of them to get here:
Code: | +-------------+-------------+-------------+
| 15 15 6 | 4 7 2 | 9 3 8 |
| 2 4 37 | 39 8 19 | 17 5 6 |
| 9 8 37 | 13 5 6 | 12 27 4 |
+-------------+-------------+-------------+
| 4 2 5 | 7 6 8 | 3 9 1 |
| 3 6 8 | 29 12 19 | 5 4 7 |
| 7 9 1 | 5 4 3 | 8 6 2 |
+-------------+-------------+-------------+
| 6 15 24 | 128 3 45 | 27 78 9 |
| 58 7 24 | 28 9 45 | 6 1 3 |
| 18 3 9 | 6 12 7 | 4 28 5 |
+-------------+-------------+-------------+ |
This is a BUG+1: R7C4 must be <2>.
Otherwise your XY-wing <128> in R89 says R8C1 is not <8>. It solves the puzzle without any of the UR's!
Still, I think, a nice example of uniqueness arguments!
Keith |
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AZ Matt
Joined: 03 Nov 2005 Posts: 63 Location: Hiding under my desk in Phoenix AZ USA
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Posted: Tue Aug 15, 2006 4:46 pm Post subject: Uniqueness theory |
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I did note the potential URs, but the xy-wing jumped out at me as I was looking at them and it solved the puzzle.
If only the puzzle didn't have the xy-wing solve -- it would be unique in my (limited) experience, and my solve on the R37C78 would have in fact been criotical. (I get discouraged when I think I've found a strong solve, and it turns out there was a simpler way to do it.)
I realize now that uniqueness theory has always been critical to my solving techniques for seriously difficult puzzles. It is that imbalance, the lack of symetry, the sense that a certain group of numbers just can't quite fit into the allotted space, that points the way -- almost invariably -- to a significant and helpful solution.
Thanks for breaking the puzzle down, Keith. |
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