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		Earl
 
 
  Joined: 30 May 2007 Posts: 677 Location: Victoria, KS
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				 Posted: Wed Feb 13, 2008 3:32 pm    Post subject: Feb 13 VH | 
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				An x-wing, then a  skyscraper (-7's) will finish it off.
 
 
 	  | Code: | 	 		  
 
+---------------+------------+--------------+
 
| 1     25   26 | 4  7   9   | 68  58   3   |
 
| 3579  3579 4  | 15 68  368 | 2   157  67  |
 
| 357   8    36 | 15 2   36  | 467 1457 9   |
 
+---------------+------------+--------------+
 
| 23459 3459 7  | 29 489 1   | 489 6    248 |
 
| 249   49   8  | 6  3   5   | 1   479  247 |
 
| 2349  6    1  | 7  489 248 | 5   3489 248 |
 
+---------------+------------+--------------+
 
| 8     47   9  | 3  1   46  | 67  2    5   |
 
| 47    1    5  | 29 469 246 | 3   78   678 |
 
| 6     23   23 | 8  5   7   | 49  49   1   |
 
+---------------+------------+--------------+
 
 | 	  
 
Play this puzzle online at the Daily Sudoku site | 
			 
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		Marty R.
 
 
  Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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				 Posted: Wed Feb 13, 2008 4:39 pm    Post subject:  | 
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				| I did a multi-coloring on 6, which I think wasn't a factor, then a Type 4 UR on 15 solved it. | 
			 
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		Johan
 
 
  Joined: 25 Jun 2007 Posts: 206 Location: Bornem  Belgium
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				 Posted: Wed Feb 13, 2008 4:51 pm    Post subject:  | 
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				The possible [24] UR* in R56C19 eliminates <7> in R7C7, three possible ways to avoid the DP(Deadly Pattern)
 
 
A. R56C1=|9| => R5C2=|4| => R7C2=|7| 
 
 
B. R5C9={7}  => R5C8={9} => R5C2={4} => R7C2={7}
 
 
C. R6C9=<8>  => R4C7=<9> => R9C7=<4> => R3C7=<7> 
 
 
 	  | Code: | 	 		  +--------------------------+--------------------------+--------------------------+
 
| 1         25        26   | 4          7       9     | 68       58        3     |
 
| 3579      79        4    | 15         68      368   | 2        157       67    |
 
| 57        8         36   | 15         2       36    | 4<7> C   1457      9     |
 
+--------------------------+--------------------------+--------------------------+
 
| 35        35        7    | 29        489      1     | 8<9>     6         248   |
 
|*24|9|   {|4|}9      8    | 6         3        5     | 1        7{9}     *24{7} |
 
|*24|9|     6         1    | 7         489      248   | 5        3        *24<8> |
 
+--------------------------+--------------------------+--------------------------+
 
| 8      AB 4{|7|}    9    | 3         1        46    | 6-[7]    2         5     |
 
| 47        1         5    | 29        469      246   | 3        78        678   |
 
| 6         23        23   | 8         5        7     |<4>9      49        1     |
 
+--------------------------+--------------------------+--------------------------+ | 	 
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		tlanglet
 
 
  Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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				 Posted: Wed Feb 13, 2008 4:59 pm    Post subject:  | 
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				I found a x-wing at r28c59 that removed <6> @ r28c6 (which may not have been useful), but a xy-wing with pivot @ r7c7 and pincers @ r1c7 & r8c8 deleted the 8 at r1c8 which broke the puzzle open.
 
 
Ted | 
			 
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		tlanglet
 
 
  Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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				 Posted: Wed Feb 13, 2008 5:09 pm    Post subject:  | 
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				 	  | Marty R. wrote: | 	 		  | I did a multi-coloring on 6, which I think wasn't a factor, then a Type 4 UR on 15 solved it. | 	  
 
 
Marty,
 
 
Could your Type 4 UR also be viewed as a Type 3 UR using the <47> in r23c8 as a pseudo-single square plus the <79> in r5c8 and the <49> in r9c8 to form a locked set <479> thereby elilminating the <7> in r8c8?
 
 
Ted | 
			 
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		sdq_pete
 
 
  Joined: 30 Apr 2007 Posts: 119 Location: Rotterdam, NL
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				 Posted: Wed Feb 13, 2008 5:30 pm    Post subject:  | 
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				A single XY wing was enough for me: 678 pivot R7C7.
 
 
Peter | 
			 
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		Marty R.
 
 
  Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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				 Posted: Wed Feb 13, 2008 5:42 pm    Post subject:  | 
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				 	  | Quote: | 	 		  Marty,
 
 
Could your Type 4 UR also be viewed as a Type 3 UR using the <47> in r23c8 as a pseudo-single square plus the <79> in r5c8 and the <49> in r9c8 to form a locked set <479> thereby eliminating the <7> in r8c8?  | 	  
 
I'm sorry Ted, I don't know. I think the strong link was on 1, so removal of the 5s solved the puzzle. | 
			 
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		Asellus
 
 
  Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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				 Posted: Wed Feb 13, 2008 11:26 pm    Post subject:  | 
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				Ted,
 
 
Yes, that 15 UR is also Type 3 and eliminates the <7> as you have noted. | 
			 
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		George Woods
 
 
  Joined: 28 Mar 2006 Posts: 304 Location: Dorset UK
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				 Posted: Wed Feb 13, 2008 11:51 pm    Post subject: 1st Move Solution!!!!! | 
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				| This VH has an XY as a possible first move (as proved by putting the resulting 5 in r1c8) in draw/play which then grades the reulting puzzle as easy! | 
			 
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		tlanglet
 
 
  Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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				 Posted: Thu Feb 14, 2008 2:36 am    Post subject:  | 
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				Thanks all for your responses.
 
 
Ted | 
			 
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