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VH+ 072721

 
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immpy



Joined: 06 May 2017
Posts: 455

PostPosted: Tue Jul 27, 2021 2:22 pm    Post subject: VH+ 072721 Reply with quote

Hello all, enjoy the puzzle...

Code:

+-------+-------+-------+
| 6 . . | . . . | 7 . . |
| . 8 . | . 3 . | 6 . . |
| . 1 . | . . 4 | . 5 9 |
+-------+-------+-------+
| 8 . 5 | . . . | 4 . . |
| . . . | . 2 . | . 9 . |
| . . 9 | . . . | . . . |
+-------+-------+-------+
| 5 . 2 | 4 . 3 | . . . |
| 3 . . | . . . | 9 7 . |
| . 9 8 | . . 2 | . . 3 |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

cheers...immp
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Clement



Joined: 24 Apr 2006
Posts: 1058
Location: Dar es Salaam Tanzania

PostPosted: Tue Jul 27, 2021 4:35 pm    Post subject: VH+072721 Reply with quote

Code:

+---------------+---------------------+--------------------+
| 6    5     34 | 129     18     19   | 7     1238    148  |
| 9    8     47 | 1257    3      157  | 6     12      14   |
| 2    1     37 | 67*     8-67*  4    | 38    5       9    |
+---------------+---------------------+--------------------+
| 8    2     5  | 1379    17     1679 | 4     136     167  |
| 4    36    1  | 3578    2      5678 | 38    9       5678 |
| 7    36    9  | 1358    4      1568 | 2     1368    1568 |
+---------------+---------------------+--------------------+
| 5    7     2  | 4       9      3    | 1     68      68   |
| 3    46    46 | 18      5      18   | 9     7       2    |
| 1    9     8  | 67*     67*    2    | 5     4       3    |
+---------------+---------------------+--------------------+

Type 1 UR(67)r39c45, r3c5<>67; stte
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TomC



Joined: 30 Oct 2020
Posts: 110
Location: Wales

PostPosted: Tue Jul 27, 2021 6:26 pm    Post subject: Reply with quote

As an alternative to the 67 UR

r2c8<> 1 as if you stick to rows 2 and 3 you have a chain 1 - 4 - 7 - 3 - 8 which means r1c9 has nothing in it
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Mogulmeister



Joined: 03 May 2007
Posts: 888

PostPosted: Fri Jul 30, 2021 3:42 pm    Post subject: Reply with quote

That's a decent contradiction.

(1)r2c8-(1=4)r8c9-(4=7)r2c3-(7=3)r3c3-(3=8)r3c7-(8=14)r12c9-(1)r2c8
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Mogulmeister



Joined: 03 May 2007
Posts: 888

PostPosted: Tue Aug 03, 2021 1:37 pm    Post subject: Reply with quote

As a post script there is another way using an ALS (Almost Locked Set) or to be accurate an AALS (Almost Almost Locked Set).



We have two ALS interacting:

Green {1,3,6,8} in (n-1=) 3 squares

Beige {1,2,3,4,8} in (n-1=) 4 squares

The restricted common should be 3 with the common candidate being 1 which can be removed from r2c8 because it can "see" all the other 1's in both ALS.

There's a wrinkle though.

The restricted common definition is bust because there's another 3 in r3c7. Otherwise it would fit and all would be well.

So logically we have a situation:

Either the ALS xz is true or the 3 is true in r3c7.

IF ALS is true then r2c8 <>1

If 3 is true (3)r3c7-(3=7)r3c3-(7=4)r2c3-(4=1)r2c9-r2c8 so r2c8 <>1

Makes the same elimination so all good.
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