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Jul 3 VH

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Clement

Joined: 24 Apr 2006
Posts: 1113
Location: Dar es Salaam Tanzania

Posted: Sun Jul 03, 2016 12:00 am Post subject: Jul 3 VH

Code:

+----------------+------------+--------------+
| 1479 2 147 | 8 5 19 | 3 6 14 |
| 1489 49 148 | 3 2 6 | 7 459 1458 |
| 13689 369 5 | 14 149 7 | 18 29 128 |
+----------------+------------+--------------+
| 2 7 14 | 9 13 5 | 6 8 34 |
| 146 46 9 | 2 8 13 | 5 34 7 |
| 5 8 3 | 7 6 4 | 2 1 9 |
+----------------+------------+--------------+
| 3789 35 78 | 6 139 139 | 4 235 12358 |
| 3489 3459 6 | 14 7 2 | 18 35 1358 |
| 34 1 2 | 5 34 8 | 9 7 6 |
+----------------+------------+--------------+

X-Wing on 1 in col 47; rc3c159, r8c9 <>1 and
XY-Wing 34-1 pivoted in r9c5; r7c5 <>1 opens
XY-Wing 23-9 pivoted in r7c8; r3c5 <> 9; stte

JC Van Hay

Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium

Posted: Sun Jul 03, 2016 7:11 am Post subject:

Code:

+-----------------+---------------+---------------------+
| 1479 2 147 | 8 5 19 | 3 6 14 |
| 1489 49 148 | 3 2 6 | 7 459 145 |
| 36 36 5 | 14 149 7 | (18) 29 1(28) |
+-----------------+---------------+---------------------+
| 2 7 14 | 9 13 5 | 6 8 34 |
| 146 46 9 | 2 8 13 | 5 34 7 |
| 5 8 3 | 7 6 4 | 2 1 9 |
+-----------------+---------------+---------------------+
| 378 35 78 | 6 139 139 | 4 235 358(2-1) |
| 3489 3459 6 | 4-1 7 2 | 8(1) 35 358(1) |
| 34 1 2 | 5 34 8 | 9 7 6 |
+-----------------+---------------+---------------------+

L3-Wing{1C7, 8R3, 2C9} -> -{1r7c9}; Pointing{1B9} -> -{1r8c4}; stte

George Woods

Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK

Posted: Tue Jul 05, 2016 9:47 am Post subject: Removing the 5 from r7c8

Clement's Final wing needs the 5 to be removed from r7c8 Proving that this cell is not 5 can be done thus - if it were 5 then the 28 in cells r78c9 give cell r3c9 desolate. However this type of logic is not usual for a VH problem.

bat999

Joined: 09 Jul 2015
Posts: 55
Location: UK

Posted: Wed Jul 06, 2016 3:56 pm Post subject:

Code:

.------------------.-----------------.--------------------.
| 1479 2 147 | 8 5 19 | 3 6 14 |
| 1489 49 148 | 3 2 6 | 7 459 145 |
| 36 36 5 | c14 149 7 | c18 9-2 c128 |
:------------------+-----------------+--------------------:
| 2 7 14 | 9 13 5 | 6 8 34 |
| 146 46 9 | 2 8 13 | 5 34 7 |
| 5 8 3 | 7 6 4 | 2 1 9 |
:------------------+-----------------+--------------------:
| 378 a35 78 | 6 b139 b139 | 4 a235 1358-2 |
| 3489 3459 6 | b14 7 2 | 18 35 1358 |
| 34 1 2 | 5 34 8 | 9 7 6 |
'------------------'-----------------'--------------------'

(2=3)r7c28 - (3=4)r7c56,r8c4 - (4=2)r3c479 => -2 r3c8,r7c9; stte
Cool

dongrave

Joined: 06 Mar 2014
Posts: 572

Posted: Thu Jul 07, 2016 5:54 am Post subject: Re: Removing the 5 from r7c8

George Woods wrote:

Clement's Final wing needs the 5 to be removed from r7c8
Proving that this cell is not 5 can be done thus - if it were 5 then the 28 in cells r78c9 give cell r3c9 desolate. However this type of logic is not usual for a VH problem.

No, that's not right George. The 5 gets removed from r7c8 with just Clement's wings and basics. Clement's initial grid has a hidden 36 pair in row 3 so r3c12 = 36. Then his X Wing removes 1 from r3c59 and r8c9. The 34-1 XY Wing removes 1 from r7c5 which leaves a lone 1 in column 5 so r4c5=1 which means r5c6<>1 so it's 3 and r4c3<>1 so it's 4 so r5c2<>4 so it's 6 so r3c2<>6 so it's 3 so r7c2<>3 so it's 5 so r7c8<>5.

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