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		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
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				|  Posted: Fri Mar 01, 2013 11:06 pm    Post subject: Impossible Menneske No. 03 |   |  
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				| Not as impossible as No. 2? 
 
  	  | Code: |  	  | M6912824 Impossible (4007) +-------+-------+-------+
 | 8 3 . | 7 4 . | . . . |
 | . . 6 | . . . | . . 9 |
 | 2 . . | 6 . . | . 8 . |
 +-------+-------+-------+
 | . . 4 | . . 8 | . . . |
 | . 9 . | . . . | . 3 . |
 | . . . | 1 . . | 7 . . |
 +-------+-------+-------+
 | . 5 . | . . 2 | . . 8 |
 | 9 . . | . . . | 5 . . |
 | . . . | . 1 . | . 6 4 |
 +-------+-------+-------+
 
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 Play this puzzle online at the Daily Sudoku site
 
 Keith
 
 Last edited by keith on Sun Mar 17, 2013 4:31 am; edited 1 time in total
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		| JC Van Hay 
 
 
 Joined: 13 Jun 2010
 Posts: 494
 Location: Charleroi, Belgium
 
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				|  Posted: Sat Mar 02, 2013 10:09 am    Post subject: |   |  
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				| #1. LS and LC; UP25 
 Solving NP(37)r38c9 ...
 
 #2. Chain[6] : 4r2c1=(4-6)r7c1=(6-7)r7c5=FXWing(7R27)-(7=59)r13c3 :=> -5r2c1 	  | Code: |  	  | +-----------------------+------------------+-------------------+ | 8        3      (59)  | 7    4      159  | 126   125    1256 |
 | 1-5(47)  14(7)  6     | 28   28     135  | 134   15(7)  9    |
 | 2        147    (579) | 6    359    1359 | 134   8      37   |
 +-----------------------+------------------+-------------------+
 | 13567    1267   4     | 235  23567  8    | 1269  1259   1256 |
 | 1567     9      257   | 245  2567   4567 | 8     3      1256 |
 | 356      268    2358  | 1    23569  3569 | 7     4      256  |
 +-----------------------+------------------+-------------------+
 | (46)     5      13(7) | 349  3(67)  2    | 139   19(7)  8    |
 | 9        46     12    | 348  3678   3467 | 5     12     37   |
 | 37       278    2378  | 359  1      357  | 239   6      4    |
 +-----------------------+------------------+-------------------+
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 #3. Chain[3] : 7r3c9=(7-5)r2c8=(5-3)r2c6=3r2c7 :=> -3r3c9; LS and LC -> UP31
 
 Solving B9 ...
 
 #4. Chain[10] : Kraken Cell (147)r2c1 -> 1r7c3=9r7c7 :=> -1r7c9 	  | Code: |  	  | +------------------------+--------------------+------------------+ | 8       3       59     | 7      4      159  | 126    125  126  |
 | (147)   147     6      | 28     28     135  | 34     15   9    |
 | 2       (14)    59     | 6      5(3)   1359 | (34)   8    7    |
 +------------------------+--------------------+------------------+
 | 156(7)  126(7)  4      | 23     2(37)  8    | 126    9    1256 |
 | 16      9       2(7)   | 245    257    47   | 8      3    16   |
 | 35      28      238    | 1      9      6    | 7      4    25   |
 +------------------------+--------------------+------------------+
 | 6(4)    5       (13)   | 3(49)  6(3)   2    | -1(9)  7    8    |
 | 9       46      12     | 48     678    47   | 5      12   3    |
 | (37)    278     238(7) | 359    1      35   | 29     6    4    |
 +------------------------+--------------------+------------------+
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 1r2c1-(1=4)r3c2-(4=3)r3c7-3r3c5=*[3r7c5=(3-7)r4c5=7r4c12-7r5c3=7r9c3-(7=3)r9c1]-(3=1)r7c3
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 4r2c1-4r7c1=(4-9)r7c4=9r7c7
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 7r2c1-(7=3)r9c1-(3=1)r7c3
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		| oaxen 
 
 
 Joined: 10 Jul 2006
 Posts: 96
 
 
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				|  Posted: Sat Mar 02, 2013 4:00 pm    Post subject: |   |  
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				| We will se. Now I shall ask my butler to prepare a nice cup of tea and start the work. |  | 
	
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		| DonM 
 
 
 Joined: 15 Sep 2009
 Posts: 51
 
 
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				|  Posted: Sun Mar 03, 2013 12:37 am    Post subject: |   |  
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				|  	  | oaxen wrote: |  	  | We will se. Now I shall ask my butler to prepare a nice cup of tea and start the work. | 
 
 Don't forget the pencil & paper so you don't forget the solution this time.
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		| oaxen 
 
 
 Joined: 10 Jul 2006
 Posts: 96
 
 
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				|  Posted: Sun Mar 03, 2013 11:47 am    Post subject: |   |  
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				| Don't forget the pencil & paper so you don't forget the solution this time. 
 I started in block H to find out wich ones of the fives is correct. Turned out to be R9C6. That gives a few other correct numbers and eliminations. My next step was to check the sixes in the same block H. Six in R7C5 leads to a complete solution.
 Best with Menneske is that they always demand at least a two step solution. Thank you Keith for providing them to this site. It is more fun to take part in a discussion.
 Lars
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		| DonM 
 
 
 Joined: 15 Sep 2009
 Posts: 51
 
 
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				|  Posted: Mon Mar 11, 2013 7:49 pm    Post subject: |   |  
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				|  	  | oaxen wrote: |  	  | Don't forget the pencil & paper so you don't forget the solution this time. 
 I started in block H to find out wich ones of the fives is correct. Turned out to be R9C6.
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 oaxen, I'm just interested: How did you determine which of the 5s were correct in box 8 (your block H)?
 
 Last edited by DonM on Mon Mar 11, 2013 8:06 pm; edited 1 time in total
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		| DonM 
 
 
 Joined: 15 Sep 2009
 Posts: 51
 
 
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				|  Posted: Mon Mar 11, 2013 8:01 pm    Post subject: |   |  
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				| Finally got some time to get to this which IMO was the more difficult of the first 4 Menneske Impossibles: 
 Menneske Impossible 4 (ER=8.3) SSTS (post Simple Sudoku Technique Set):
 
  	  | Code: |  	  | *--------------------------------------------------------------------*
 | 8      3      59     | 7      4      159    | 126    125    1256   |
 | 1457   147    6      | 28     28     135    | 134    157    9      |
 | 2      147    579    | 6      359    1359   | 134    8      37     |
 |----------------------+----------------------+----------------------|
 | 13567  1267   4      | 235    23567  8      | 1269   1259   1256   |
 | 1567   9      257    | 245    2567   4567   | 8      3      1256   |
 | 356    268    2358   | 1      23569  3569   | 7      4      256    |
 |----------------------+----------------------+----------------------|
 | 46     5      137    | 349    367    2      | 139    179    8      |
 | 9      46     12     | 348    3678   467    | 5      12     37     |
 | 37     278    2378   | 359    1      357    | 239    6      4      |
 *--------------------------------------------------------------------*
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 1. aur(14)r23c27[(7)r23c2=(3)r23c7]-(3=7)r3c9 => -7r3c3 -> np(59)r13c3: -5r2c1, -5r56c3
 2. (5)r2c8=(5-3)r2c6=r2c7-grp(3)r79c7=r8c9-(3=7)r3c9 => -7r2c8 -> several singles -> lc(7)b8: -7r9c6 -> nq(1359)r1239c6 => r6c6=6 -> r6c5=9
 
 
  	  | Code: |  	  | *--------------------------------------------------------------------*
 | 8      3      59     | 7      4      159    | 126    125    1256   |
 | 147    147    6      | 28     28     135    | 134    15     9      |
 | 2      14     59     | 6      35     1359   | 134    8      7      |
 |----------------------+----------------------+----------------------|
 | 13567  1267   4      | 235    2357   8      | 126    9      1256   |
 | 1567   9      27     | 245    257    47     | 8      3      1256   |
 | 35     28     238    | 1      9      6      | 7      4      25     |
 |----------------------+----------------------+----------------------|
 | 46     5      13     | 349    36     2      | 19     7      8      |
 | 9      46     12     | 48     678    47     | 5      12     3      |
 | 37     278    2378   | 359    1      35     | 29     6      4      |
 *--------------------------------------------------------------------*
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 3. aur(28)r69c23[(3)r6c3=(2)r9c7]-r8c8=(2-1)r8c3=(1)r7c3 => -3r7c3
 stte
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		| oaxen 
 
 
 Joined: 10 Jul 2006
 Posts: 96
 
 
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				|  Posted: Tue Mar 12, 2013 9:15 am    Post subject: |   |  
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				| I started in block H to find out wich ones of the fives is correct. Turned out to be R9C6.[/quote] oaxen, I'm just interested: How did you determine which of the 5s were correct in box 8 (your block H)?[/quote]
 
 I checked them both simultaneously. I guess that is the meaning with Sudoko. Find some favourable bivalues and work further from them. Rather soon one find that in the both cases one or more boxes have the same values - and after that it is normal to go on with pure basics technique
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		| DonM 
 
 
 Joined: 15 Sep 2009
 Posts: 51
 
 
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				|  Posted: Tue Mar 12, 2013 9:49 pm    Post subject: |   |  
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				|  	  | oaxen wrote: |  	  | I started in block H to find out wich ones of the fives is correct. Turned out to be R9C6. | 
 
  	  | DonM wrote: |  	  | oaxen, I'm just interested: How did you determine which of the 5s were correct in box 8 (your block H)?
 | 
 
 
  	  | oaxen wrote: |  	  | I checked them both simultaneously. I guess that is the meaning with Sudoko. Find some favourable bivalues and work further from them. Rather soon one find that in the both cases one or more boxes have the same values - and after that it is normal to go on with pure basics technique
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 Thanks. I think I've got it.
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