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Still more Eureka

 
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Sun Nov 11, 2012 1:01 am    Post subject: Still more Eureka Reply with quote

This is the Fiendish from Nov. 9 that Dan posted on the other forum. How would my first move be notated? The 9 in A makes B=4 which creates an 89 pair in C which takes out the 9 from D and then 59 from E. I'm fairly confident that what I wrote is incorrect.

Code:
 *-------------------------------------------------------------*
 | 7      56     1     | 89    2     56    | 89    3     4     |
 | 689    3      4     | 7     89    56    | 2     589   1     |
 | 89     2      589   | 1     4     3     | 7     589   6     |
 |---------------------+-------------------+-------------------|
 | 2     D59    E569   | 39    7     4     | 139   1-69  8     |
 | 1      479   -679   | 2389  89    28    | 349  A69    5     |
 | 3     C489   C89    | 6     5     1     |B49    2     7     |
 |---------------------+-------------------+-------------------|
 | 4      678    3     | 5     16    9     | 18    178   2     |
 | 689    689    2     | 48    16    7     | 5     148   3     |
 | 5      1      78    | 248   3     28    | 6     478   9     |
 *-------------------------------------------------------------*

(6=9)r5c8-(9=4)r6c7-(4=NP89)-(9=5)r4c2-(59=6)r4c3-->r5c8, r6c3<>6
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Sun Nov 11, 2012 10:51 am    Post subject: Re: Still more Eureka Reply with quote

Marty R. wrote:
This is the Fiendish from Nov. 9 that Dan posted on the other forum. How would my first move be notated? The 9 in A makes B=4 which creates an 89 pair in C which takes out the 9 from D and then 59 from E. I'm fairly confident that what I wrote is incorrect.

Code:
 *-------------------------------------------------------------*
 | 7      56     1     | 89    2     56    | 89    3     4     |
 | 689    3      4     | 7     89    56    | 2     589   1     |
 | 89     2      589   | 1     4     3     | 7     589   6     |
 |---------------------+-------------------+-------------------|
 | 2     D59    E569   | 39    7     4     | 139   1-69  8     |
 | 1      479   -679   | 2389  89    28    | 349  A69    5     |
 | 3     C489   C89    | 6     5     1     |B49    2     7     |
 |---------------------+-------------------+-------------------|
 | 4      678    3     | 5     16    9     | 18    178   2     |
 | 689    689    2     | 48    16    7     | 5     148   3     |
 | 5      1      78    | 248   3     28    | 6     478   9     |
 *-------------------------------------------------------------*

(6=9)r5c8-(9=4)r6c7-(4=NP89)-(9=5)r4c2-(59=6)r4c3-->r5c8, r6c3<>6


Three comments:
1: You forgot to include the cells involved in the NP89 term; otherwise it is a valid statement although it is not necessary to include the notation "NP".
(6=9)r5c8-(9=4)r6c7-(4=89)r6c23-(9=5)r4c2-(59=6)r4c3-->r5c8, r6c3<>6

2: The next two terms dealing with the NP59 are awkward but probably understandable. An alternative is to treat the NP59 in the same manner as the prior NP89.
(6=9)r5c8-(9=4)r6c7-(4=89)r6c23-(59=6)r4c23-->r5c8, r6c3<>6

3: Another alternative for the notation is to treat the four cells in box 4 as a single als(45689).
(6=9)r5c8-(9=4)r6c7-(4=6)r64c23 --> r5c8, r6c3<>6
I have also seen other posts that include the "als" notation when the als is large/involved.
(6=9)r5c8-(9=4)r6c7-als(4=6)r65c23 --> r5c8, r6c3<>6

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Sun Nov 11, 2012 6:03 pm    Post subject: Reply with quote

Thanks Ted and welcome back. Very Happy
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