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		| PeteGrant 
 
 
 Joined: 17 Feb 2006
 Posts: 10
 Location: Saranac Lake, New York
 
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				|  Posted: Sun May 07, 2006 12:27 pm    Post subject: WebSudoku 'Evil' Puzzle |   |  
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				| Ran into a dead-end with an "Evil" puzzle from WebSudoku.com.  Here's what I have so far: 
 
  	  | Code: |  	  | +-----------------------------------+
 |  .  .  5  |  6  7  .  |  .  9  4  |
 |  9  .  4  |  3  5  .  |  .  .  .  |
 |  .  .  7  |  9  4  .  |  5  8  .  |
 |-----------+-----------+-----------|
 |  .  5  2  |  7  3  .  |  4  1  .  |
 |  .  .  .  |  4  .  .  |  .  5  .  |
 |  .  4  .  |  8  .  5  |  7  .  .  |
 |-----------+-----------+-----------|
 |  .  2  .  |  5  8  4  |  1  .  .  |
 |  4  .  .  |  1  .  3  |  .  .  5  |
 |  5  1  .  |  2  .  7  |  .  4  .  |
 +-----------------------------------+
 
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 The Draw facility show that I should place a 9 in r4c6 but I fail to see the pattern that dictates this.  Here's what I have as possibilities:
 
 
  	  | Code: |  	  | +------------------------------------------------------------------+
 |  1238     38     5  |      6      7   128  |    23     9     4   |
 |     9    678     4  |      3      5   128  |    26   267 12678   |
 |  1236     36     7  |      9      4    12  |     5     8  1236   |
 +------------------------------------------------------------------+
 |    68      5     2  |      7      3    69  |     4     1    689  |
 | 13678  36789 13689  |      4     12    69  | 23689     5  23689  |
 |   136      4  1369  |      8     12     5  |     7   236   2369  |
 +------------------------------------------------------------------+
 |   367      2   369  |      5      8     4  |     1   367   3679  |
 |     4   6789   689  |      1     69     3  |  2689   267      5  |
 |     5      1  3689  |      2     69     7  |  3689     4   3689  |
 +------------------------------------------------------------------+
 
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 What am I missing?
 
 TIA,
 Pete
 ________
 Janesville Assembly
 
 Last edited by PeteGrant on Thu Feb 03, 2011 10:05 am; edited 1 time in total
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		| ravel 
 
 
 Joined: 21 Apr 2006
 Posts: 536
 
 
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				|  Posted: Sun May 07, 2006 1:00 pm    Post subject: |   |  
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				| There is a box/line or box/box interaction (number 1), which leads to a hidden pair. |  |  
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		| PeteGrant 
 
 
 Joined: 17 Feb 2006
 Posts: 10
 Location: Saranac Lake, New York
 
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				|  Posted: Sun May 07, 2006 1:34 pm    Post subject: |   |  
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				| Thank you, ravel, for responding, but I don't see the hidden pair -- yet.  Could you point out  the cells that constitute the interaction? 
 Thanks
 Pete
 ________
 vapormatic vaporizer
 
 Last edited by PeteGrant on Thu Feb 03, 2011 10:05 am; edited 1 time in total
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		| Angel 
 
 
 Joined: 26 Mar 2006
 Posts: 31
 
 
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				|  Posted: Sun May 07, 2006 2:26 pm    Post subject: |   |  
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				| From the postion you posted, I would note that since 7 is already placed in box 1 you can eliminate it from the possibilities for r2c2. This then leads to a triple {3,6,8} in r1c2, r2c2, r3c2. Therefore there is a pair {1,2} in r1c1, r3c1. Also there is then a pair {1,2} in r3c1, r3c6, which reduces the possibilities for r3c9. Then looking at box 3 you will have another triple (and check the 8 which is already placed but still appears as a candidate). 
 Over to you after that.
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		| ravel 
 
 
 Joined: 21 Apr 2006
 Posts: 536
 
 
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				|  Posted: Sun May 07, 2006 6:52 pm    Post subject: |   |  
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				|  	  | PeteGrant wrote: |  	  | Thank you, ravel, for responding, but I don't see the hidden pair -- yet.  Could you point out  the cells that constitute the interaction? 
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 The way, Angel did it - spotting the triple, which gives the pair, is a bit easier, but i did not see the triple because of the 7.
 
 The 1 in box 1 can only be in column 1 (therefore must be there), so it cannot be in the rest of the column (box/line interaction) and it can be eliminated from r5c1 and r6c1. This leaves the hidden pair 12 in r13c1.
 Sorry, there is no box/box elimination for the same.
 
 PS: I dont really understand the hint r4c6=9. i would need the following chain to get that:
 r4c6=6 => r5c6=9 => r6c3=9 => r7c9=9 => r4c6=9
 which is very complicated compared to a naked triple.
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		| TKiel 
 
 
 Joined: 22 Feb 2006
 Posts: 292
 Location: Kalamazoo, MI
 
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				|  Posted: Sun May 07, 2006 11:08 pm    Post subject: |   |  
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				| There is a swordfish on 9's that excludes 9 from r5c6, leaving r4c6 as the only place for a 9 in box 5 but it also leaves r5c6 as a naked single, which seems a more appropriate hint. |  |  
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		| ravel 
 
 
 Joined: 21 Apr 2006
 Posts: 536
 
 
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				|  Posted: Mon May 08, 2006 7:34 am    Post subject: |   |  
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				| Well spotted   Looking for the swordfish i first saw the x-wing in rows 6 and 7, that kills the 9 in r4c9 => r4c6=9.
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		| PeteGrant 
 
 
 Joined: 17 Feb 2006
 Posts: 10
 Location: Saranac Lake, New York
 
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				|  Posted: Mon May 08, 2006 10:40 am    Post subject: |   |  
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				| Thank you all for your input.  This was one of those cases where the more I looked, the more I missed   
 BTW, WebSudoku's "evil" puzzles seem to be of about the same difficulty as DailySudoku's "hard".  I haven't dared to try the "very hard" yet....
 ________
 3/15
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