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Vanhegan fiendish July 13, 2012

 
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arkietech



Joined: 31 Jul 2008
Posts: 1733
Location: Northwest Arkansas USA

PostPosted: Fri Jul 13, 2012 5:28 am    Post subject: Vanhegan fiendish July 13, 2012 Reply with quote

Code:

 *-----------*
 |15.|..8|6..|
 |.4.|...|.98|
 |.9.|3..|1..|
 |---+---+---|
 |5..|2.1|.4.|
 |4.1|...|8.6|
 |.7.|8.4|..9|
 |---+---+---|
 |..4|..6|.7.|
 |76.|...|.8.|
 |..8|4..|.62|
 *-----------*
 

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Clement



Joined: 24 Apr 2006
Posts: 686
Location: Dar es Salaam Tanzania

PostPosted: Fri Jul 13, 2012 8:15 am    Post subject: Vanhegan fiendish July 13, 2012 Reply with quote

After the Basics
Code:

+------------+---------------+------------+
| 1   5  27  | 79  2479 8    | 6   3  47  |
| 23  4  237 | 6   1    257  | A257 9  8   |
| 8   9  6   | 3   2457 257  | 1   B25 457 |
+------------+---------------+------------+
| 5   8  9   | 2   6    1    | 37  4  37  |
| 4   D23 1   | 579 3579 3579 | 8   C25 6   |
| 6   7  23  | 8   35   4    | 25  1  9   |
+------------+---------------+------------+
| F239 E23 4   | 15  8    6    | 359 7  135 |
| 7   6  5   | 19  239  239  | 4   8  13  |
| 39  1  8   | 4   357  357  | 359 6  2   |
+------------+---------------+------------+
Single's Chain's on 2. A=>B=>C=>D=>E=>F; r2c1<>2 solves it.
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tlanglet



Joined: 17 Oct 2007
Posts: 2461
Location: Northern California Foothills

PostPosted: Fri Jul 13, 2012 1:12 pm    Post subject: Reply with quote

An alternate solution................

5r5c8=5r6c7-(5=3)r6c5-r6c3=r5c2-AUR(39)r79c17[(3)r7c2=(3)r4c7]-(3=7)r4c9-(47=5)r13c9; r3c8<5>
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Marty R.



Joined: 12 Feb 2006
Posts: 5179
Location: Rochester, NY, USA

PostPosted: Fri Jul 13, 2012 4:31 pm    Post subject: Reply with quote

Code:

+------------+---------------+------------+
| 1   5  27  | 79  2479 8    | 6   3  47  |
| 23  4  237 | 6   1    257  | 257 9  8   |
| 8   9  6   | 3   2457 257  | 1   25 457 |
+------------+---------------+------------+
| 5   8  9   | 2   6    1    | 37  4  37  |
| 4   23 1   | 579 3579 3579 | 8   25 6   |
| 6   7  23  | 8   35   4    | 25  1  9   |
+------------+---------------+------------+
| 239 23 4   | 15  8    6    | 359 7  135 |
| 7   6  5   | 19  239  239  | 4   8  13  |
| 39  1  8   | 4   357  357  | 359 6  2   |
+------------+---------------+------------+

Play this puzzle online at the Daily Sudoku site

Use the DP/UR on 39 in boxes 79 to create pincers. Either r7c1=2 or r79c7=5. The latter sets r6c7=2. Transport 2 from r7c1 to r5c2; r5c8, r6c3<>2.
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SudoQ



Joined: 02 Aug 2011
Posts: 127

PostPosted: Fri Jul 13, 2012 7:07 pm    Post subject: Reply with quote

This pattern also solves it:
Code:
|--------------|-----------------|--------------|
| 1    5   27  | 79   2479  8    | 6    3   47  |
|(23)  4  27-3 | 6    1     257  |(2)57 9   8   |
| 8    9   6   | 3    2457  257  | 1    25  457 |
|--------------|-----------------|--------------|
| 5    8   9   | 2    6     1    | 37   4   37  |
| 4    23  1   | 579  3579  3579 | 8    25  6   |
| 6    7  (23) | 8    35    4    |(2)5  1   9   |
|--------------|-----------------|--------------|
| 239  23  4   | 15   8     6    | 359  7   135 |
| 7    6   5   | 19   239   239  | 4    8   13  |
| 39   1   8   | 4    357   357  | 359  6   2   |
|--------------|-----------------|--------------|
/SudoQ
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arkietech



Joined: 31 Jul 2008
Posts: 1733
Location: Northwest Arkansas USA

PostPosted: Fri Jul 13, 2012 10:37 pm    Post subject: Reply with quote

Another one
Code:
 *-----------------------------------------------------------*
 | 1     5    *27    | 79    2479  8     | 6     3     47    |
 |*23    4    *237   | 6     1     257   |*257   9     8     |
 | 8     9     6     | 3     2457  257   | 1     25    457   |
 |-------------------+-------------------+-------------------|
 | 5     8     9     | 2     6     1     | 37    4     37    |
 | 4     23    1     | 579   3579  3579  | 8     25    6     |
 | 6     7     3-2   | 8     35    4     |*25    1     9     |
 |-------------------+-------------------+-------------------|
 | 239   23    4     | 15    8     6     | 359   7     135   |
 | 7     6     5     | 19    239   239   | 4     8     13    |
 | 39    1     8     | 4     357   357   | 359   6     2     |
 *-----------------------------------------------------------*
Empty Rectangle (ER) 2

2r1c3=r2c13-r2c7=2r6c7 => -2r3c3; stte

if r1c3 is not a 2 then r6c7 is a 2
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