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Free Press November 11, 2011

 
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keith



Joined: 19 Sep 2005
Posts: 3178
Location: near Detroit, Michigan, USA

PostPosted: Fri Nov 11, 2011 3:16 pm    Post subject: Free Press November 11, 2011 Reply with quote

Code:
Puzzle: FP111111
+-------+-------+-------+
| . . 5 | . . . | 8 . . |
| 1 8 6 | . 4 . | . 3 . |
| . 7 . | . . . | . . 1 |
+-------+-------+-------+
| . . . | 7 . 4 | . 1 . |
| . . 7 | . 6 . | 9 . . |
| . 6 . | 9 . 3 | . . . |
+-------+-------+-------+
| 8 . . | . . . | . 4 . |
| . 4 . | . 5 . | 3 6 9 |
| . . 9 | . . . | 5 . . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

Keith
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arkietech



Joined: 31 Jul 2008
Posts: 1727
Location: Northwest Arkansas USA

PostPosted: Fri Nov 11, 2011 5:08 pm    Post subject: Reply with quote

Code:
X Wing r6c9<>4
 *-----------------------------------------------------------*
 | 349   23    5     | 1     237   27-6  | 8     29   a46    |
 | 1     8     6     | 25    4     9     | 27    3     257   |
 | 39    7     234   |f36    238   2568  | 4-6   259   1     |
 |-------------------+-------------------+-------------------|
 | 5     9    c38    | 7     28    4     | 26    1    b36    |
 | 34    1     7     | 258   6     258   | 9     28    34    |
 | 2     6     48    | 9     1     3     | 47    578   578   |
 |-------------------+-------------------+-------------------|
 | 8     5    d23    |e36    9     67    | 1     4     27    |
 | 7     4     1     | 28    5     28    | 3     6     9     |
 | 6     23    9     | 4     37    1     | 5     278   278   |
 *-----------------------------------------------------------*
s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6
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ronk



Joined: 07 May 2006
Posts: 397

PostPosted: Fri Nov 11, 2011 6:45 pm    Post subject: Reply with quote

arkietech wrote:
s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6

An s-wing would have a bivalued cell at its center. This is an l-wing with transport (I think).
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Marty R.



Joined: 12 Feb 2006
Posts: 5164
Location: Rochester, NY, USA

PostPosted: Fri Nov 11, 2011 6:47 pm    Post subject: Reply with quote

I hacked my way through to the finish using an X-Wing, M-Wing and three XY-Wings, with three of the moves involving pincer transports.
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keith



Joined: 19 Sep 2005
Posts: 3178
Location: near Detroit, Michigan, USA

PostPosted: Sat Nov 12, 2011 3:04 am    Post subject: Reply with quote

After basics:
Code:
+-------------------+-------------------+-------------------+
| 2349  239   5     | 1236  1237  1267  | 8     29    46    |
| 1     8     6     | 25    4     9     |B27    3     257   |
| 2349  7     234   | 23568 238   2568  | 46    259   1     |
+-------------------+-------------------+-------------------+
| 2359  239   238   | 7     28    4     |C26    1    -23568 |
| 234   123   7     | 1258  6     1258  | 9     28   -2348  |
| 245   6     1248  | 9     128   3     |C247   2578 -24578 |
+-------------------+-------------------+-------------------+
| 8     5     23    | 236   9     267   | 1     4    A27    |
| 7     4     12    | 128   5     128   | 3     6     9     |
| 6     123   9     | 4     1237  127   | 5     278   278   |
+-------------------+-------------------+-------------------+

Cool! A grouped M-wing.

7 in A forces 7 in B. Not 2 in B forces 2 in one of C. Eliminating 2 in B6C9.

Nice move, though it does not solve the puzzle.

Keith
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arkietech



Joined: 31 Jul 2008
Posts: 1727
Location: Northwest Arkansas USA

PostPosted: Sat Nov 12, 2011 3:09 am    Post subject: Reply with quote

arkietech wrote:
Code:
s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6

I find that it matches what Norm calls an Inverted w wing.
Code:
iW-Wing:  (Y)s = (Y-X)a = (X)b - (X)c = (X-Y)d = (Y)t
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ronk



Joined: 07 May 2006
Posts: 397

PostPosted: Sat Nov 12, 2011 4:57 am    Post subject: Reply with quote

arkietech wrote:
arkietech wrote:
Code:
s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6

I find that it matches what Norm calls an Inverted w wing.
Code:
iW-Wing:  (Y)s = (Y-X)a = (X)b - (X)c = (X-Y)d = (Y)t

That's an ill-advised name. All other wings have three strong links ... except for the x-wing, of course.
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keith



Joined: 19 Sep 2005
Posts: 3178
Location: near Detroit, Michigan, USA

PostPosted: Sat Nov 12, 2011 8:53 am    Post subject: Reply with quote

ronk wrote:
arkietech wrote:
arkietech wrote:
Code:
s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6

I find that it matches what Norm calls an Inverted w wing.
Code:
iW-Wing:  (Y)s = (Y-X)a = (X)b - (X)c = (X-Y)d = (Y)t

That's an ill-advised name. All other wings have three strong links ... except for the x-wing, of course.
Though, wings can often be extended by another couple of strong links while keeping basically the same logic.

Keith
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daj95376



Joined: 23 Aug 2008
Posts: 3855

PostPosted: Sat Nov 12, 2011 5:28 pm    Post subject: Reply with quote

In Norm's inverse/inverted wing patterns, he exchanges weak inferences and strong inferences, and then adds a strong inference to the front and end to complete the pattern. (at least, that's been my observation.)

Code:
 W-Wing:         (X=Y)a - (Y)b = (Y)c - (Y=X)d
iW-Wing:  (X)s = (X-Y)a = (Y)b - (Y)c = (Y-X)d = (X)t
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