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Puzzle 11/07/17: ~ XY

 
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daj95376



Joined: 23 Aug 2008
Posts: 3855

PostPosted: Sun Jul 17, 2011 3:57 pm    Post subject: Puzzle 11/07/17: ~ XY Reply with quote

Code:
 +-----------------------+
 | 4 . 3 | . . 5 | 6 7 . |
 | . . 2 | . . . | 3 5 . |
 | 5 1 8 | . . . | 2 9 4 |
 |-------+-------+-------|
 | . . . | 7 . . | 1 . 3 |
 | . . . | . . . | . . 5 |
 | 3 . . | . . 8 | . 2 . |
 |-------+-------+-------|
 | 2 5 7 | 3 . . | . 1 . |
 | 1 3 6 | . . 9 | 7 . . |
 | . . 4 | 1 2 . | . . 6 |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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Marty R.



Joined: 12 Feb 2006
Posts: 5179
Location: Rochester, NY, USA

PostPosted: Mon Jul 18, 2011 4:51 am    Post subject: Reply with quote

Hidden UR (49); r5c7<>4, r6c4<>9
DP (68), boxes 46. R5c1=7 or r45c8=4; common outcome; r4c8<>8
Type 1 UR (67); r5c2<>67
XY-Wing (584), flightless with transport; r6c2<>4
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tlanglet



Joined: 17 Oct 2007
Posts: 2461
Location: Northern California Foothills

PostPosted: Mon Jul 18, 2011 1:50 pm    Post subject: Reply with quote

Marty, I believe that your first step is a one-stepper when viewed differently.........

(5=9)r4c3-(9=1)r5c3-(1=26)r45c6-(6=4)r7c6-(4=8)r7c7-aur(49)r56c47[(8)r5c7=(5)r6c4]; r6c3<>5

Ted
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daj95376



Joined: 23 Aug 2008
Posts: 3855

PostPosted: Mon Jul 18, 2011 4:24 pm    Post subject: Reply with quote

My solver's solution reduces to two steps:

Code:
 +--------------------------------------------------------------+
 |  4     9     3     |  2    *18    5     |  6     7    *18    |
 |  67    67    2     |  89   *18+49 14    |  3     5    *18    |
 |  5     1     8     |  6     7     3     |  2     9     4     |
 |--------------------+--------------------+--------------------|
 |  68    246   59    |  7     59    26    |  1     468   3     |
 |  678   2467  19    |  49    3     126   |  489   468   5     |
 |  3     46    159   |  459   16    8     |  49    2     7     |
 |--------------------+--------------------+--------------------|
 |  2     5     7     |  3     468   46    |  48    1     9     |
 |  1     3     6     |  58    458   9     |  7     48    2     |
 |  9     8     4     |  1     2     7     |  5     3     6     |
 +--------------------------------------------------------------+
 # 46 eliminations remain

 r12c59  <18> UR Type 1.2224             <> 18   r2c5

XY-Chain: (1=4)r2c6 - (4=9)r2c5 - (9=5)r4c5 - (5=9)r4c3 - (9=1)r5c3  =>  r5c6<>1

Which can be treated as a single-stepper:
Code:

(1=4)r2c6 - (4=UR=9)r2c5 - (9=5)r4c5 - (5=9)r4c3 - (9=1)r5c3  =>  r5c6<>1

This is a perspective on a UR Type 1 that I hadn't considered previously.
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Marty R.



Joined: 12 Feb 2006
Posts: 5179
Location: Rochester, NY, USA

PostPosted: Mon Jul 18, 2011 4:35 pm    Post subject: Reply with quote

tlanglet wrote:
Marty, I believe that your first step is a one-stepper when viewed differently.........

(5=9)r4c3-(9=1)r5c3-(1=26)r45c6-(6=4)r7c6-(4=8)r7c7-aur(49)r56c47[(8)r5c7=(5)r6c4]; r6c3<>5

Ted

Ted, I am more than capable of turning a one-stepper into a four-stepper; I've done it many times. However, I don't understand Eureka so I don't know what your one-stepper is.
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tlanglet



Joined: 17 Oct 2007
Posts: 2461
Location: Northern California Foothills

PostPosted: Mon Jul 18, 2011 8:28 pm    Post subject: Reply with quote

daj95376 wrote:
My solver's solution reduces to two steps:

Code:
 +--------------------------------------------------------------+
 |  4     9     3     |  2    *18    5     |  6     7    *18    |
 |  67    67    2     |  89   *18+49 14    |  3     5    *18    |
 |  5     1     8     |  6     7     3     |  2     9     4     |
 |--------------------+--------------------+--------------------|
 |  68    246   59    |  7     59    26    |  1     468   3     |
 |  678   2467  19    |  49    3     126   |  489   468   5     |
 |  3     46    159   |  459   16    8     |  49    2     7     |
 |--------------------+--------------------+--------------------|
 |  2     5     7     |  3     468   46    |  48    1     9     |
 |  1     3     6     |  58    458   9     |  7     48    2     |
 |  9     8     4     |  1     2     7     |  5     3     6     |
 +--------------------------------------------------------------+
 # 46 eliminations remain

 r12c59  <18> UR Type 1.2224             <18>  r5c6<1>  r5c6<>1

This is a perspective on a UR Type 1 that I hadn't considered previously.

Danny, that is very cool Cool. It is something I definitely have not thought about before although I once used a Type 2 pattern to link.

Ted
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Tue Jul 19, 2011 9:36 am    Post subject: Reply with quote

Here's a simple als one stepper..
Code:
(8=5)r8c4 - ant(5=469)r6c247 - (6)r6c5=r7c5 ; r7c5<>8
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