dailysudoku.com Forum Index dailysudoku.com
Discussion of Daily Sudoku puzzles
 
 FAQFAQ   SearchSearch   MemberlistMemberlist   UsergroupsUsergroups   RegisterRegister 
 ProfileProfile   Log in to check your private messagesLog in to check your private messages   Log inLog in 

Still stuck on Mar.9

 
Post new topic   Reply to topic    dailysudoku.com Forum Index -> Daily Sudoku puzzles
View previous topic :: View next topic  
Author Message
Sarah
Guest





PostPosted: Fri Mar 10, 2006 7:23 pm    Post subject: Still stuck on Mar.9 Reply with quote

I can't even get as far as the previous poster ...

I've only got:

5?69?7??4
?9?5?467?
74????195
46??59??1
359???426
8??64???9
9?4?????8
?8549????
6??8?594?

I don't see the logic in determining the 5's in rows 6&7, or the 7 in r9c8.

Any guidance?
Thanks,
Sarah
Back to top
keith



Joined: 19 Sep 2005
Posts: 3164
Location: near Detroit, Michigan, USA

PostPosted: Fri Mar 10, 2006 9:29 pm    Post subject: Reply with quote

Look at the possibilities in C8. There is a pair, which will enable you to solve the two <5>'s.

If you need a further clue, there is a triple (and a hidden pair) in block 5, which will lead to resolving C4 into two pairs.

Keith
Back to top
View user's profile Send private message
Guest






PostPosted: Sun Mar 12, 2006 6:13 pm    Post subject: Reply with quote

Sarah:

I assume you were able to follow Keith's logic, but just in case you couldn't find the pair, r1c8 and r4c8 are <3,8>. Therefore, r6c8 must be a 5, which means that r7c7 is also a 5.

- Emily
Back to top
alanr555



Joined: 01 Aug 2005
Posts: 193
Location: Bideford Devon EX39

PostPosted: Sun Mar 12, 2006 11:44 pm    Post subject: Reply with quote

Code:

I have already posted a solution on the other heading
and so I will confine this posting to the steps in reaching
the position at the start of the other topic.

There are THREE cells to be resolved r6c8, r7c7, r8c9

++

Starting from the position initially posted, I used Mandatory
Pairs to record additional information before proceeding to
derivation of the candidates. Normally I would have the M/P
data marked already but some had been eliminated on my
own solution which I completed on 10th.

The markings include

Box1- 8 in col3
Box2- 1 in col5, 6 in row3
Box3- 8 in row 1, 2 askew
Box4- 1 in row 6
Box5- Triple in row 5 (pairs for 1,7,8)
          Mutual Reception (23)
Box6- 8 in row4
(NB 7 in col 7 is NOT included yet)
Box7- No pairs at this stage
Box8- No pairs at this stage
Box9- ONE Mutual Receptions (16)
(NB The other on 23 NOT derived yet)

To continue:

a) Row/Box Interesect on '5' requires the
    '5' in box 9 to be in row 7. There are
    two possibilities r7c7 and r7c8.
b) R7c8 is NOT available for the '5' as it
    is in "Mutual Reception" with r8c8 with (16).
   This is one of the techniques with Mandatory
   Pairs:- If two cells are in Mutual Reception,
   no 'interloper' is allowed.
c) Thus r7c7 MUST be '5'

++

d) Slice/Dice on '5' gives r6c8 to be '5' as well.

++

e) The '7' in box 6 MUST be in col 7 as col 9 is
    full and col 8 already has a '7'

f) This means that ONLY col 9 is available for
   the '7' in box 9 - meaning r8c9 or r9c9.

g) Looking at row 8 there is a '7' already in
    col1 and col 6 plus there WILL be a '7'
    in col 6 as per 'e' above.

h) This means that of the unresolved cells in
    row 8 ONLY r8c9 is a possibility for the '7'
    Thus r8c9 is '7' by "Sole Position"!

++++

"Sole Position" is one of the harder things for a
human solver to spot as it involves eliminating
the impossible rather than being guided directly
to the solution by the logic of the situation as
would be the case with "sole candidates".

In fact it was this "sole position" that I missed in
my original working and which led me to resort to
candidate profiles. I had a (237) triple in box 9
rather than the (23) Mutual Reception that arises
once the '7' in r8c9 has been resolved.

Sole position is easy for computer solvers and
somewhat easier for humans if the candidate
profiles have been derived. It is the only occurrence
of the digit in a whole row/col/region - easily spotted
if one maintains a record of how often a digit appears
in each such row/col/region BUT how many human
solvers would keep such a record in short term memory?

++++

Once these three cells have been resolved the remainder
of the puzzle CAN be solved using Mandatory Pairs. The
process is described in the other topic heading for March 9th.


For further information on this, it is possible to view
the following link:

Mandatory Pairs - October Notes.


Alan Rayner BS23 2QT
Back to top
View user's profile Send private message
Display posts from previous:   
Post new topic   Reply to topic    dailysudoku.com Forum Index -> Daily Sudoku puzzles All times are GMT
Page 1 of 1

 
Jump to:  
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum


Powered by phpBB © 2001, 2005 phpBB Group