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Guest
Guest
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 Posted: Tue Feb 07, 2006 11:39 am Post subject: 7 Feb 2006 |
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Hi every one,
I am a relative new comer to suduko. I am stuck on todays puzzle. This is how far I've got:
| Code: | ----94-76
----38-95
--9-728--
-517-3--4
-3642175-
4--9-5-1-
--381----
76-249---
19-35---- |
Can anyone give me a few hints on how to get to the next step, please?
Many Thanks
Jude |
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Steve R
Joined: 24 Oct 2005
Posts: 289
Location: Birmingham, England
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| Posted: Tue Feb 07, 2006 12:08 pm Post subject: 7 Feb 2006 |
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Jude:
There is a pair in the third row.
Check where 5 and 6 may be placed. Only two cells admit these values. Now, keeping in mind that these two cells are to be filled by a 5 or a 6, there is only one place for a 3 in the top left-hand box.
I hope this trick gets you past the hurdle. Good luck!
Steve |
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igolf4birdies
Joined: 01 Feb 2006
Posts: 4
Location: Russell Springs, KY
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| Posted: Thu Feb 09, 2006 4:29 pm Post subject: 2/7/06 Puzzle |
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I'm stuck. I need some logic for my next step. I had already found the 5,6 pair in the third row as well as the 2,7 pair in the sixth row. But now I'm stuck.
3 8 _ _ 9 4 _ 7 6
_ _ _ _ 3 8 _ 9 5
_ _ 9 _ 7 2 8 _ _
_ 5 1 7 _ 3 _ 2 4
_ 3 6 4 2 1 7 5 _
4 _ _ 9 _ 5 _ 1 _
_ _ 3 8 1 _ _ _ _
7 6 _ 2 4 9 _ _ _
1 9 _ 3 5 _ _ _ _
Thanks in advance.
Rick |
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Steve R
Joined: 24 Oct 2005
Posts: 289
Location: Birmingham, England
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| Posted: Fri Feb 10, 2006 1:33 am Post subject: 2/7/06 Puzzle |
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If it’s any consolation, this ranks in my mind at about as tough as puzzles on this site get.
You will see that the 2 in the top right-hand box must occupy column7. Equally the 6 in the middle right-hand box occupies column 7.
Taking account of all these facts, what is left for r9c7?
Steve |
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Guest
Guest
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| Posted: Sun Feb 12, 2006 2:40 pm Post subject: |
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Thanks Steve, I managed to get out, but need to practice that trick a bit more.
Jude |
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jeeperndbb
Guest
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| Posted: Mon Feb 13, 2006 10:11 pm Post subject: The two |
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| How did we get the 2 in r4c8? |
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David Bryant
Joined: 29 Jul 2005
Posts: 559
Location: Denver, Colorado
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| Posted: Mon Feb 13, 2006 11:03 pm Post subject: Re: The two |
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| jeeperndbb wrote: | | How did we get the 2 in r4c8? |
The short answer is it can't fit anywhere else in row 4. Let's look at the grid.
| Code: | 3 8 _ _ 9 4 _ 7 6
_ _ _ _ 3 8 _ 9 5
_ _ 9 _ 7 2 8 _ _
_ 5 1 7 _ 3 _ _ 4
_ 3 6 4 2 1 7 5 _
4 _ _ 9 _ 5 _ 1 _
_ _ 3 8 1 _ _ _ _
7 6 _ 2 4 9 _ _ _
1 9 _ 3 5 _ _ _ _ |
-- We can't put either an "8" or a "9" at r2c1. r3c1. or r7c1. So the "hidden pair" {8, 9} must lie in r4c1 & r5c1. In other words, we can't put a "2" at r4c1.
-- We can't put a "2" at r4c5 because of the "2" at r5c5.
-- The "2" in the top right 3x3 box must lie in r1c7 or r2c7 because of the "2" at r3c6. So we can't put a "2" at r4c7.
-- r4c8 is the only spot left for a "2" in row 4. dcb |
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