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lda697
Joined: 21 Nov 2005 Posts: 1

Posted: Mon Nov 21, 2005 6:58 pm Post subject: Nov 21 su doku help 


Hey, Lee here. This is my first message. For today's 11/21 su doku, I was able to identify all the 2s and some 3s. I highlighted 4 Xs in red where I know it has to be a "3".I also identified some 9s and one 6, so that my puzzle looks like this:
93X X5X 827
XX8 9X2 53X
X2X X8X XXX
XXX 7XX XX2
XXX 2X5 XXX
3X2 XX1 XXX
XXX X2X X9X
273 X69 4XX
694 X1X 2X3
I was wondering if somebody out there could identify another number or two and explain how they figured it out. Sincerly Confused! 

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Guest

Posted: Mon Nov 21, 2005 8:53 pm Post subject: 


Hey, Lee here. This is my first message. For today's 11/21 su doku, I was able to identify all the 2s and some 3s. I highlighted 4 Xs in red where I know it has to be a "3".I also identified some 9s and one 6, so that my puzzle looks like this:
93X X5X 827
XX8 9X2 53X
X2X X8X XXX
XXX 7XX XX2
XXX 2X5 XXX
3X2 XX1 XXX
XXX X2X X9X
273 X69 4XX
694 X1X 2X3
I was wondering if somebody out there could identify another number or two and explain how they figured it out. Sincerly Confused!
Hi Lee,
Your lower red X's in the lower middle quadrant are incorrect as a 3 since there is a 3 in that row.
I am not much further along than you, but have identified a couple of 7's. Mine looks like this:
93X X5X 827
XX8 972 53X
X2X X8X XXX
XXX 7XX XX2
XXX 2X5 XXX
3X2 XX1 XXX
XXX X2X X9X
273 XX9 4XX
694 X17 1X3
The 7 in the Lower Middle quadrant had to be in Column 6 because Column 4 has a 7 and Row 8 has a 7 thus eliminating all squares in Column 4 and 5 in this quadrant. Therefore the 7 in the Upper Middle quadrant has to be in Column 5 and there is only one opening there at Column 5 Row 2.
After looking at the positioning of the 3 and 4 in both the Lower Left and Lower Right quadrant, I determined that the 3 and 4 in the Lower Middle quadrant had to be along row 7, thus eliminating the posibility of a 7 being at Column 6 Row 7 and leaving only Column 6 Row 9 for the 7.
Boy does that sound confusing. I'm sure there is an easier way to explain all that.
Curtis[/b] 

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David Bryant
Joined: 29 Jul 2005 Posts: 559 Location: Denver, Colorado

Posted: Mon Nov 21, 2005 9:34 pm Post subject: Here's a hint 


Hi, Lee!
You already found the "6" in r8c5. Good! Now look at r2c5. It has to be a "7" because there must be a "7" in column 5, and "7" can't fit anywhere else in that column (notice the "7" already in the middle center 3x3 box, and that column 5 is full in the bottom center 3x3 box).
With the "7" filled in you can see that the three digits in r4c5, r5c5, and r6c5 must be {3, 4, 9 }, in some order. Combining those with the {1, 2, 5, 7} already appearing in the middle center 3x3 box you can infer that the pair {6, 8} must appear in r4c6 and r6c4, the diagonally opposite corners of that middle center 3x3 box. This doesn't help you place another number right now, but it will be useful information pretty soon.
To get the next numbers, concentrate on row 7. You already have 2/3 of the lower left 3x3 box filled in, so you know that {1, 5, 8} must fit in r7c1, r7c2, & r7c3, in some order. Now look at the "3" and "4" appearing in both row 8 and row 9. Since all of these are outside of the bottom center 3x3 box you can see that the pair {3,4} must occupy the two cells r7c4 & r7c6. And now if you count what's left over in row 7 you'll see that the pair {6, 7} must occupy r7c7 & r7c9 in some order ... but since there's a "7" at r1c9 you can put the "7" in r7c7 and the "6" at r7c9.
I hope that's enough of a hint! dcb 

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Guest

Posted: Tue Nov 22, 2005 3:46 am Post subject: 


Anonymous wrote:  Hey, Lee here. This is my first message. For today's 11/21 su doku, I was able to identify all the 2s and some 3s. I highlighted 4 Xs in red where I know it has to be a "3".I also identified some 9s and one 6, so that my puzzle looks like this:
93X X5X 827
XX8 9X2 53X
X2X X8X XXX
XXX 7XX XX2
XXX 2X5 XXX
3X2 XX1 XXX
XXX X2X X9X
273 X69 4XX
694 X1X 2X3
I was wondering if somebody out there could identify another number or two and explain how they figured it out. Sincerly Confused!
Hi Lee,
Your lower red X's in the lower middle quadrant are incorrect as a 3 since there is a 3 in that row.
I am not much further along than you, but have identified a couple of 7's. Mine looks like this:
93X X5X 827
XX8 972 53X
X2X X8X XXX
XXX 7XX XX2
XXX 2X5 XXX
3X2 XX1 XXX
XXX X2X X9X
273 XX9 4XX
694 X17 1X3
The 7 in the Lower Middle quadrant had to be in Column 6 because Column 4 has a 7 and Row 8 has a 7 thus eliminating all squares in Column 4 and 5 in this quadrant. Therefore the 7 in the Upper Middle quadrant has to be in Column 5 and there is only one opening there at Column 5 Row 2.
After looking at the positioning of the 3 and 4 in both the Lower Left and Lower Right quadrant, I determined that the 3 and 4 in the Lower Middle quadrant had to be along row 7, thus eliminating the posibility of a 7 being at Column 6 Row 7 and leaving only Column 6 Row 9 for the 7.
Boy does that sound confusing. I'm sure there is an easier way to explain all that.
Curtis[/b] 
Thanks Curtis for your insightful observation about the 3&4s in the lower quadrants enabling you to identify two 7 locatons! I learned a lot from that. Also, regarding your pointing out my red Xs being in conflict with the 3 already there, I later realized that I placed the red Xs inthe wrong row...it should have been up two rows...but that is water under the brige! Also, you may have a typo in the last row as you have a 1 in the botttom right quadrant when there already is a 1. Thanks again for taking time to help me out. Lee 

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